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k0ka [10]
3 years ago
12

5. What is the difference between an object's SPEED and its VELOCITY?

Physics
1 answer:
Svetach [21]3 years ago
3 0
Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.
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There is a refrigerator running in a room, the heat flowing into the refrigerator from the outside is 40 J/s, and the refrigerat
Mamont248 [21]

Answer:

(A) 140 j/sec (b) 1.26 K

Explanation:

We have given the heat heat flowing into the refrigerator = 40 J/sec

Work done = 40 W

(a) So the heat discharged from the refrigerator =heat\ flowing\ in\ refrigerator+work\ done=40+100=140j/sec

(b) Total heat absorbed =140 j/sec =140\times 3600=504000j/hour

Let the temperature be \Delta T

Heat absorbed per hour =504000 [tex]=400\times 10^3\times \Delta T

So  \Delta T=\frac{504000}{400000}=1.26K

8 0
3 years ago
How many days are in a year on mars
Triss [41]
687 days
hope this helps
stay safe
brainliest is appreciated
7 0
3 years ago
30 points plz help ill do anything... literally anything.
ruslelena [56]

Answer:

1. 2.5s

Explanation:

1. For time, divide Distance / speed

25m / 10

=2.5s

3 0
3 years ago
calculate how much charge passes through the LED in 1 hour if the current flowing in the circuit below is 350mA
Morgarella [4.7K]

Given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.

<h3>What is Current?</h3>

Current is simply the rate of flow of charged particles i.e electrons caused by EMF or voltage.

If a charge passes through the cross-section of a conductor in a given time, the current I is expressed as;

I = Q/t

Where Q is the charge and t is time elapsed.

Given the data in the question;

  • Time elapsed t = 1hr = 3600s
  • Current I = 350mA = 0.35A
  • Charge Q = ?

We substitute our given values into the expression above to determine the charge.

I = Q/t

Q = I × t

Q = 0.35A × 3600s

Q = 1260C

Therefore,  given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.

Learn more about current here: brainly.com/question/3192435

#SPJ1

3 0
2 years ago
Show all your work clearly on the scratch paper) Two in-phase loudspeakers that emit sound with the same frequency are placed al
Darya [45]

Answer:

Explanation:

The speed of sound in air to be 343 m/s.

Given:

distance 'd' = 5 m

L = 12 m

It can be concluded that path difference must be equal to half of the wavelength when person is observing destructive interference'y' at 1 m distance from the equidistant position

Since

λ/2 = yd/L

λ/2 = (1 x 5)/12

λ = 0.833m

Frequency of the sound is given by,

f = v / λ => 343 / 0.833

f=411.6 Hz

8 0
3 years ago
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