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3 years ago

5. What is the difference between an object's SPEED and its VELOCITY?

1 answer:

3 0

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.

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How can a small boy balance a big boy on a sea saw?

irina [24]

Answer:

Answer: Say the big boy is 40kg and the small boy is 20kg... ... ...then by the rule that moments around a fulcrum or pivot should be equal for equilibrium, the distance of big boy from pivot=half of dist of small boy from pivot

7 0

3 years ago

Read 2 more answers

A proton, traveling with a velocity of 4.6 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 6.0

Kobotan [32]

Answer:

$B = 0.0815 T$

since the direction of force is along south so the magnetic field must be upwards

Explanation:

Force on moving charge in magnetic field is given as

$F = q(\vec v \times \vec B)$

here we know this is force on proton

so we have

$q = 1.6 \times 10^{-19} C$

$F = 6.0 \times 10^{-14} (-\hat j) N$

also we know that the velocity of charge is

$v = 4.6 \times 10^6 \hat i m/s$

now from above formula we have

$(6.0 \times 10^{-14}) = (1.6 \times 10^{-19})(4.6 \times 10^6)B$

$B = 0.0815 T$

since the direction of force is along south so the magnetic field must be upwards

6 0

4 years ago

Electrons (mass m, charge –e) are accelerated from rest through a potential difference V and are then deflected by a magnetic fi

adell [148]

Answer:

$r=\dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}$

Explanation:

Let m and e are the mass and charge of an electron. It is accelerated from rest through a potential difference V and are then deflected by a magnetic field that is perpendicular to their velocity. Let v is the velocity of the electron. It can be calculated as :

$\dfrac{1}{2}mv^2=eV$

$v=\sqrt{\dfrac{2eV}{m}}$

When the electron enters the magnetic field, the centripetal force is balanced by the magnetic force as :

$\dfrac{mv^2}{r}=evB$

$r=\dfrac{mv}{eB}$

$r=\dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}$

So, the radius of the resulting electron trajectory is $\dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}$ . Hence, this is the required solution.

8 0

3 years ago

3. a car takes off with initial velocity of 20m/s and move with uniform acceleration of 12m/s2 for 20s. It maintained a constant

lions [1.4K]

The total distance traveled by the car at the given velocity and time is 900 m.

The given parameters:

initial velocity of the car, u = 20 m/s
acceleration of the car, a = 12 m/s²
time of motion of the car, t = 20 s
final time = 30 s
final acceleration = 2 m/s²

The final time of motion of car before coming to rest is calculated as follows;

$v_f = v_0 -at\\\\0 = 20 - 2t\\\\t = 10 \ s$

The graph of the car's motion is in the image uploaded.

The total distance traveled by the car is calculated as follows;

$total \ distance = A \ + B \ + C\\\\total \ distance = (\frac{1 }{2} \times 20 \times 20) \ + (20 \times 30) \ + (\frac{1}{2}\times 10 \times 20)\\\\total \ distance = 900 \ m$

Thus, the total distance traveled by the car at the given velocity and time is 900 m.

Learn more about velocity-time graph here: brainly.com/question/24874645

3 0

3 years ago

A complete digestive system is found in bears.

GrogVix [38]

Hi! I believe the correct answer is A. Do you have any other questions I can help you with? I would be glad too.

- Amber

4 0

3 years ago