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Alenkinab [10]
3 years ago
8

Please help I will mark brainliest, I don't know how to do this

Mathematics
1 answer:
ZanzabumX [31]3 years ago
3 0

Answer:follow me on ig lol

Step-by-step explanation:

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For the rational expression 2x^2-7x-15/x^2-25, do both of the following,
Mrrafil [7]

Answer:

a. \frac{2x + 3}{x+5}

b. x ≠ -5 (Vertical asymptote) and x ≠ 5 (Hole)

Step-by-step explanation:

Factor the numerator (Grouping):

2x^2 - 7x - 15              

Two numbers that multiply to -30 and add to -7 = -3 and 10

[2x^2 - 10x] + [3x - 15]

(2x + 3)(x - 5)

Factor the denominator (Difference of Two Squares):

x^2 - 25 = (x +5)(x-5)

Factored Expression:

(x - 5) can be factored out of top and bottom as a hole-

\frac{(2x + 3)(x - 5)}{(x + 5)(x - 5)} = \frac{2x + 3}{x+5}

Variable Restrictions:

Denominator ≠ 0

x + 5 = 0\\x = -5

Vertical asymptote at x = -5 ⇒ x ≠ -5

3 0
3 years ago
What number divided by 2 3 4 5 6 has a remainder of 1 but when divided by 7 has no remainder?
Afina-wow [57]
301

We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...

However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.

Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7). 

301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.

Hope this all makes sense.
3 0
3 years ago
Help me please *an image is attached*
Mashutka [201]

Answer:

its C

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of si
kozerog [31]

The ratios of sin x° and cos y° are 15/8.

We have given that,

Use the image below to answer the following question.

We have to determine to find the value of sin x° and cos y°.

By applying Pythagoras theorem in the triangle given in the picture,

<h3>What is the Pythagoras theorem?</h3>

(Hypotenuse)² = (leg 1)² + (leg 2)²

PO² = (15)² + 8²

PO² = 225 + 64

PO = √289

PO = 17

By applying the sine rule in the given triangle,

sin(x°) = Opposie side/hypotenous

         = 15/17

cos(y°) = Adjucent side/hypotenous

          = 8/17

The relation between the ratio of sin(x) and cos(x) will be,

\frac{sinx}{cosx} =\frac{\frac{15}{17} }{\frac{8}{17} }

=\frac{15}{8}

Therefore the ratios of sin x° and cos y° are 15/8.

To learn more about the trigonometric function visit:

brainly.com/question/24349828

#SPJ2

       

5 0
2 years ago
Find the geometric mean between 9 and 11
klio [65]

Step-by-step explanation:

Geometric mean is the square root of the product.

√(9 × 11) = √99 ≈ 9.950

3 0
3 years ago
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