Answer:
490849.9
Step-by-step explanation:
Answer:
The average speed of the car, in miles per hour, from 17:30 to 19:42, is 119.167 meters per second.
Step-by-step explanation:
Physically speaking, average speed (
), measured in miles per hour, is the distance travelled (
), measured in miles, divided by time (
), measured in hours. That is:
(1)
The time needed by the vehicle is:
If we know that 
and , then the average velocity of the car is:
The average speed of the car, in miles per hour, from 17:30 to 19:42, is 119.167 meters per second.
Volume is a three-dimensional scalar quantity. The volume of concrete that will have to be poured into the pool deck is 6.0185 cubic yards.
<h3>What is volume?</h3>
A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
Since an inch is equal to 1/12 of a foot. Therefore, the thickness of the pool deck is,
3 inches = 0.25 foot
If a pool deck of 650 square feet is to be laid with concrete 3" thick, then the volume of concrete that will be needed is,
Volume of concrete = 650 ft² × 0.25 ft = 162.5 ft³
Now, one yard is equal to 3 feet, therefore,
1 cubic foot = 1/27 cubic yards
162.5 cubic feet = 6.0185 cubic yards
Hence, the volume of concrete that will have to be poured into the pool deck is 6.0185 cubic yards.
Learn more about Volume:
brainly.com/question/13338592
#SPJ1
C
6x^2-13X-5=0
(3X+1)(2X-5)
3x-1=0
X=1/3. 2x-5=0. X= 5/2
Answer:
f) a[n] = -(-2)^n +2^n
g) a[n] = (1/2)((-2)^-n +2^-n)
Step-by-step explanation:
Both of these problems are solved in the same way. The characteristic equation comes from ...
a[n] -k²·a[n-2] = 0
Using a[n] = r^n, we have ...
r^n -k²r^(n-2) = 0
r^(n-2)(r² -k²) = 0
r² -k² = 0
r = ±k
a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q
We find p and q from the initial conditions.
__
f) k² = 4, so k = 2.
a[0] = 0 = p + q
a[1] = 4 = -2p +2q
Dividing the second equation by 2 and adding the first, we have ...
2 = 2q
q = 1
p = -1
The solution is a[n] = -(-2)^n +2^n.
__
g) k² = 1/4, so k = 1/2.
a[0] = 1 = p + q
a[1] = 0 = -p/2 +q/2
Multiplying the first equation by 1/2 and adding the second, we get ...
1/2 = q
p = 1 -q = 1/2
Using k = 2^-1, we can write the solution as follows.
The solution is a[n] = (1/2)((-2)^-n +2^-n).
