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3 years ago

How can a periodic table help a chemist write the chemical name of a compound from its chemical formula?

2 answers:

7 0

It's B. by identifying the elements.

Reasons:
prefixes are only used for covalent compounds.

You don't include the number of atoms when you write the chemical name of a compound.

Subscripts are basically numbers that tell how many atoms of each element is in a compound. It does not identify the name of an element.

creativ13 [48]3 years ago

4 0

Answer:

B) by identifying the elements

Explanation:

EDGE 2020 brainliest please

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You have a hard glass flask that you plug up with a stopper at room temperature (25 C) and an internal pressure of 1 atm. If you

liubo4ka [24]

Answer:

pressure of 0atm

Explanation:

5 0

3 years ago

3. How much heat (in joules) is needed to raise the temperature of 355 g of ethanol I

Rudiy27

Answer:

53676 J

Explanation:

m = 355 g

c = 2.4 J/gºC

ΔT = 63°C

q = mcΔT

= (355)(2.4)(63)

= 53676 J

6 0

3 years ago

A student dissolves 3.9g of aniline (C6H5NH2) in 200.mL of a solvent with a density of 1.05 g/mL . The student notices that the

Tresset [83]

Answer:

a. Molarity= $M =2.1x10^{-1}M$

b. Molality= $m=2.0x10^{-1}m$

Explanation:

Hello,

In this case, given the information about the aniline, whose molar mass is 93g/mol, one could assume the volume of the solution is just 200 mL (0.200 L) as no volume change is observed when mixing, therefore, the molarity results:

$M=\frac{n_{solute}}{V_{solution}} =\frac{3.9g*\frac{1mol}{93g} }{0.2L} =2.1x10^{-1}M$

Moreover, the molality:

$m=\frac{n_{solute}}{m_{solvent}} =\frac{3.9g*\frac{1mol}{93g} }{0.2L*\frac{1.05kg}{1L} } =2.0x10^{-1}m$

Best regards.

7 0

2 years ago

Pls help me in this:(

antiseptic1488 [7]

Answer:

a) 26.98

b) 3

c) 3* 1.01 = 3.03

d) 3 *16 = 48

e) 26.98 + 3.03 + 48 = 78.01

f) 6.023 * 10²³

3 0

2 years ago

Solution A is 0.44 M and reacts with 0.11 M of solution B. Assume that the value of x is 0, the value of y is 1, and r is 1.07 ×

xz_007 [3.2K]

Answer:

K, the rate constant = 9.73 × 10^(-1)/s

Explanation:

r = K × [A]^x × [B]^y

r = Rate = 1.07 × 10^(-1)/s

K = Rate constant

A and B = Concentration in mol/dm^-3

A = 0.44M

B = 0.11M

x = Order of reaction with respect to A = 0

y = Order of reaction with respect to B = 1

Solving, we get

r/([A]^x × [B]^y) = K

K = 1.07 × 10^(-1)/s/(0.44^0 × 0.11^1)= 0.9727

K = 0.9727

7 0

3 years ago