The answer is D. First, it is the segment addition postulate because the two segments make up the whole. Second, it's substitution because you are substituting EF + FG for FH.
Hope this helps!
\left[x \right] = \left[ 16+3\,y\right][x]=[16+3y] totally graphic doing ur sheets
Answer:
Step-by-step explanation:
If 
, then 
. It follows that
![\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%20%5C%5C%5Cfrac%7Bg%28x%2Bh%29-g%28x%29%7D%7Bh%7D%20%26%3D%20%5Cfrac%7B1%7D%7Bh%7D%20%5Ccdot%20%5Bg%28x%2Bh%29%20-%20g%28x%29%5D%20%5C%5C%26%3D%20%5Cfrac%7B1%7D%7Bh%7D%20%5Cleft%28%20%5Cfrac%7B1%7D%7Bx%2Bh%7D%20-%20%5Cfrac%7B1%7D%7Bx%7D%20%5Cright%29%5Cend%7Baligned%7D)
Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.
Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.
The property shown is a B: substitution property, this is when you you the know that X=Y so X can be substituted in any equation with Y and Y can be substituted in any equation with X. hope this helps
We can do this by converting the equation to vertex form:-
h = -16t^2 + 36t + 10
= -16(t^2 - 2.25t) + 10
= -16 [ (t - 1.125)^2 - (1.125)^2] + 10
= -16(t - 1.125)^2 + 20.25 + 10
= -16(t - 1.125)^2 + 30.25
So the answer is 1.13s and 30.25 ft.
= (
