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mihalych1998 [28]
3 years ago
9

The table below shows randy breuers height in inches leading into his teen years. The graph below displays a scatter plot of the

data. Which equation best represents the line of best fit for this data?
The choices are:
A. y=1.1x+23
B. y=1.25x+20
C. y=1.25x+40.67
D. y=1.4x+40.67

Mathematics
2 answers:
-Dominant- [34]3 years ago
8 0
The least-square regression line has a slope of:

m=(nΣxy-ΣyΣx)/(nΣx²-ΣxΣx)

and a y-intercept of:

b=(Σy-mΣx)/n

In this case: n=7, Σxy=4899, Σy=391, Σx=85, Σx²=1153 so

m=(7(4899)-391*85)/(7(1153)-85*85))=1058/846

b=(391*846-85*1058)/(7*846)=34408/846

So the line of best fit is:

y=(1058x+34408)/846  and if we approximated this as your answers see to have done....

y=1.25x+40.67
son4ous [18]3 years ago
8 0

Answer:

c

Step-by-step explanation:

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fgiga [73]

Answer:

7 or 8 hours, depending on the answer you're looking for

Step-by-step explanation:

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3 0
3 years ago
-35, 165 365, 565 765,<br> Is it geometric, arithmetic, neither?
Charra [1.4K]

Answer:

arithmetic

Step-by-step explanation:

I think

3 0
2 years ago
Read 2 more answers
A regular hexagon has sides of 3 feet. What is the area of the hexagon?
Dominik [7]

Answer:

13.5√(3) ft^2

Step-by-step explanation:

In this, question, we are to calculate the area of the hexagon

Mathematically, we can calculate the area of a hexagon using the formula;

A = {3√(3)/2}a^2

where a is the length of the side which is 3 feet

substituting the value of 3 into the formula, we have;

A = 3√3/2 * 3^2 = 27 √(3)/2 = 13.5√(3) ft^2

7 0
3 years ago
Which statement regarding the diagram is true?
zhenek [66]

Answer:

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Step-by-step explanation:

the 2 bottom angles equal to 180

7 0
3 years ago
What's the answer?? I don't get it
quester [9]
Okay just find something the bottom and the top number can be divided by. Like the first one 9/18. They are bithe dividable by 9 so 9÷9=1. 18÷9=2. Now put one back over two. 1/2. So your answer is one half. This is to help you learn how to do it I hope it helps.
4 0
3 years ago
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