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juin [17]
3 years ago
9

How do u solve the following equation: |r|=1

Mathematics
1 answer:
vredina [299]3 years ago
7 0
You're almost looking at the solution.  Almost.

If it only said  "  r = 1 ", then that would be the solution right there.

But it says "  | r | = 1 ", so there's a little more to it.

'r' can be either  +1  or  -1  and that equation will be a true statement.

So  +1  and  -1  are both solutions.
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If (x – 4) + 6 = 2 - (4 - 2x), then x =<br> A. -4<br> B. -2<br> C. 2<br> D. 4
blondinia [14]

Answer:

x=4

Step-by-step explanation:

Remove the parentheses and turn the 4-2x and make it into 4+2x candle the equal term -4 and should be left with x+6=2+2x then move the variable to the left and change the sign so it would be x-2x=2-6 and collect like terms so it would be -x=2-6 and then calculate that and get -x= -4

(sorry its alot)

6 0
3 years ago
Select the correct slope and y-intercept for the
Schach [20]

Answer:2. because slope can't be negative and we just did this question.

Step-by-step explanation:

4 0
2 years ago
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A 60 kg dog requires fluids at 50 mL/kg over 24 hours. Using a 10 gtt/mL set how many gtts/min will you set?
Ann [662]

50\times 10 = 500
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3 0
2 years ago
Help please!!!!!!????!!!!
zavuch27 [327]

Answer:

28 yd²

Step-by-step explanation:

find the two biggest sides

2x4

8 but there are two sides...

8*2= 16

*16*

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1x4

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4*2= 8

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4 0
2 years ago
Which classification describes the following system of equations? inconsistent and dependent consistent and dependent consistent
sveta [45]

The system of equations is consistent and independent and the solutions are x = 4, y = 5, and z = -1 option third is correct.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have three linear equations in three variables:

x - y - z = 0 ..(1)

2x - y + 2z = 1 ..(2)

x - y + z = -2 ..(3)

From the equation (1):

\rm x=y+z

Plug this value in the equation (2) and (3):

\rm 2\left(y+z\right)-y+2z=1\\\\ y+z-y+z=-2

After solving we get:

z = -1

y = 5

Plug the above two values in equation (1) we get:

x = 4

Thus, the system of equations is consistent and independent and the solutions are x = 4, y = 5, and z = -1 option third is correct.

Learn more about the linear equation here:

brainly.com/question/11897796

#SPJ1

5 0
1 year ago
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