By reading the fine details of the question, carefully and analytically, I have determined that there's no list of modifications to choose from.
The strength of the magnetic field of a solenoid depends on the electric current in its coil windings, the number of wire turns in its coil windings, and the material in its core.
In order to <em>DE</em>crease the strength of its magnetic field, any one or more of these steps could do the job:
-- DEcrease the electric current in its coil windings. This can be accomplished by decreasing the voltage of the power source that energizes the coil, and/or increasing the resistance of the wire in the coil.
-- DEcrease the number of wire turns in the coil.
-- If the solenoid has anything in its core, change the core to something with a lower magnetic 'permeability'. An Iron core will produce the greatest magnetic field strength. Air, vacuum, or NO core will produce the lowest magnetic field strength.
Answer:
P= 168258.30696 Pa
Explanation:
Given that
Mass of water vapor m = 19.00 g
Volume of water vapor V = 2.00 L
Temperature of water vapor is T = 111°C
= 384K
Molar mass of water is M = 18.0148 g/mol
Number of moles are
n = m/M
= (1.90 g)/(18.0148 g/mol)
= 0.1054 mol
Pressure inside the container is
P= nRT/V
P= 168258.30696 Pa
To develop this problem it is necessary to apply the concepts related to the angular resolution of a telescope as well as to the arc length.
The arc length can be defined as
Where
r= Radius
\theta = Angle
At the same time the angular resolution of a body is given under the proportion
Where
= Wavelength
D = Diameter
Our values are given as
Then the angle of separation of the two objects seen from the observer is of
Finally, using the proportion of the arc length, in which we have the radius and angle we can know the separation of the two objects by:
The velocity of the tennis racket after the collision 14.966 m/s.
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of tennis racket = 0.311 kg
m₂ = mass of the ball = 0.057 kg
u₁ = velocity of tennis racket before collision = 30.3 m/s
u₂ = velocity of the ball before collision = -19.2 m/s
v₁ = velocity of tennis racket after collision
v₂ = velocity of the ball after collision
Right (+) , Left (-)
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= ( 30.3 * (0.311 - 0.057) - 19.2 * 2 * 0.057 ) / ( 0.311 + 0.057)
= 14.966 m/s.
So, the velocity of the tennis racket after the collision 14.966 m/s.
Answer:
the force exerted on the dipole = 0.11 N
Explanation:
Using F = (KQq/r^2) sin ∅
the distance of dipole to the line charge will be 30 cm, hence 1 st charge on the dipole -10 micro C is 29 cm and that to + 10 micro C is 31 cm (2 cm apart).
0.91 N with -ve charge and 0.80 to +ve charge. The difference is the force on the dipole i.e 0.11 N