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ludmilkaskok [199]
3 years ago
12

An object moving north with an initial velocity of 14 m/s accelerates 5 m/s^2 for 20 seconds.what is the final velocity of the o

bject?
39 m/s
90 m/s
114 m/s
414m/s
Physics
2 answers:
bekas [8.4K]3 years ago
5 0

Answer:

Option C = 114 m/s

Explanation:

a=v-u/t

By substituting,

5=v-14/20

100=v-14

Thus, v=100+14

v= 114 m/s

Hope it helps :)

ELEN [110]3 years ago
5 0
The answer is 114 m/s good luck!!!
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A woman drives 200 miles west and then turns south and drives 375 miles. Her trip takes her 11.75 hrs. What is the woman's avera
FromTheMoon [43]

Answer:

The woman's average velocity during the trip is 36.2 miles/hour.

Explanation:

Velocity can be define as the displacement of an object per time. It is a vector quantity, and measured in m/s.

i.e velocity = \frac{displacement}{time}

From the given question,

Displacement = \sqrt{200^{2} + 375^{2}  }

                       = \sqrt{40000+140625}

                       = \sqrt{180625}

                       = 425

The displacement of woman is 425 miles.

velocity = \frac{425}{11.75}

             = 36.1702 miles/hour

The woman's average velocity during the trip is 36.2 miles/hour.

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What does the zigzag line in the circuit diagram represent
faust18 [17]
A) An electrical resistor  


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2 years ago
Which of the following statements about large scale mineral extraction is true?
Sonbull [250]

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3 years ago
A Neglecting air resistance, a ball projected straight upward so it remains in the air for 10 seconds needs an initial speed of
ololo11 [35]

Answer:

The initial velocity is 50 m/s.

(C) is correct option.

Explanation:

Given that,

Time = 10 sec

For first half,

We need to calculate the height

Using equation of motion

v^2=u^2+2gh

h =\dfrac{v^2}{2g}....(I)

For second half,

We need to calculate the time

Using equation of motion

h =ut+\dfrac{1}{2}gt_{2}^2

h=0+\dfrac{1}{2}gt_{2}^2

t_{2}=\sqrt{\dfrac{2h}{g}}

Put the value of h from equation (I)

t_{2}=\sqrt{\dfrac{2\times v^2}{g^2}}

t_{2}=\dfrac{v}{g}

According to question,

t_{1}+t_{2}=10

t_{1}=t_{2}

Put the value of t₁ and t₂

\dfrac{v}{g}+\dfrac{v}{g}=10

\dfrac{2v}{g}=10

v=\dfrac{10\times g}{2}

Here, g = 10

The initial velocity is

v=\dfrac{10\times10}{2}

v=50\ m/s

Hence, The initial velocity is 50 m/s.

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2 years ago
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