Design a Device That Minimizes the Force on an Object During a Collision

Physics

1 answer:

____ [38]2 years ago

5 0

what's your question O_- ??

you have given the essay, but wts the topic ? lol

You might be interested in

In the design of a supermarket, there are to be several ramps connecting different parts of the store. Customers will have to pu

tatuchka [14]

Answer:

3.90 degrees

Explanation:

Let g= 9.81 m/s2. The gravity of the 30kg grocery cart is

W = mg = 30*9.81 = 294.3 N

This gravity is split into 2 components on the ramp, 1 parallel and the other perpendicular to the ramp.

We can calculate the parallel one since it's the one that affects the force required to push up

F = WsinΘ

Since customer would not complain if the force is no more than 20N

F = 20

$294.3sin\theta = 20$

$sin\theta = 20/294.3 = 0.068$

$\theta = sin^{-1}0.068 = 0.068 rad = 0.068*180/\pi \approx 3.90^0$

So the ramp cannot be larger than 3.9 degrees

6 0

4 years ago

Typically, a bullet leaves a standard .50-caliber rifle (29.0-in. barrel) at a speed of 853 m/s. If it takes 1.2 milliseconds to

nirvana33 [79]

To find what a is, consider the equation v=at (v=velocity, a=acceleration, t=time interval), making a=v/t. Take the given v of 853m/s, and divide that by your time IN SECONDS, so 1.2ms=1.2*10^-3s.

a=(853)/(1.2*10^-3)=7.11*10^5 m/s^2.

Now Having F=ma, where a is your acceleration, and m=mass (which is 49*10^-3 kg),

F=(49*10^-3)(7.11*10^5)=3.48*10^4 N

Hope this helps!

3 0

4 years ago

What is the charge delivered by a current with an average of 0.54 A over 28.3 minutes?

marishachu [46]

Answer:

916.9C

Explanation:

Using Q= It

Q= 0.54A x 1698s

= 916.9C

6 0

4 years ago