Question

What is the average acceleration of the particle between 0 seconds and 4 seconds with a velocity of 2m/s

Answer 1

Explanation:

Average acceleration is defined as change in velocity divided by change in time.

Mathematically,             a = $\frac{\Delta v}{\Delta t}$

Since, it is given that change in velocity is 2 m/s. On the other hand, $t_{1}$ = 0 sec and $t_{2}$ = 4 sec.

Therefore, calculate average acceleration as follows.

                        a = $\frac{\Delta v}{\Delta t}$

                           = $\frac{\Delta v}{t_{2} - t_{1}}$

                           = $\frac{2 m/s}{4 sec - 0 sec}$

                           = 0.5 $m/s^{2}$

Therefore, we can conclude that average acceleration of the given particle is 0.5 $m/s^{2}$.