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Nady [450]
3 years ago
8

What is the average acceleration of the particle between 0 seconds and 4 seconds with a velocity of 2m/s

Physics
1 answer:
vovikov84 [41]3 years ago
6 0

Explanation:

Average acceleration is defined as change in velocity divided by change in time.

Mathematically,             a = \frac{\Delta v}{\Delta t}

Since, it is given that change in velocity is 2 m/s. On the other hand, t_{1} = 0 sec and t_{2} = 4 sec.

Therefore, calculate average acceleration as follows.

                        a = \frac{\Delta v}{\Delta t}

                           = \frac{\Delta v}{t_{2} - t_{1}}

                           = \frac{2 m/s}{4 sec - 0 sec}

                           = 0.5 m/s^{2}

Therefore, we can conclude that average acceleration of the given particle is 0.5 m/s^{2}.

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Georgia [21]

Answer:

358.9 (+/- 0.4) million years ago

Holocene Epoch, of the Quaternary Period

Devonian period

66 million years ago (prox)

521 million years ago

110,000 years ago

NW

North america became more cold when it moved NW

Explanation:

8 0
3 years ago
An object in the shape of a thin ring has radius a and mass M. A uniform sphere with mass m and radius R is placed with its cent
madreJ [45]

Answer:

F = GMmx/[√(a² + x²)]³

Explanation:

The force dF on the mass element dm of the ring due to the sphere of mass, m at a distance L from the mass element is

dF = GmdM/L²

Since the ring is symmetrical, the vertical components of this force cancel out leaving the horizontal components to add.

So, the horizontal components add from two symmetrically opposite mass elements dM,

Thus, the horizontal component of the force is

dF' = dFcosФ where Ф is the angle between L and the x axis

dF' = GmdMcosФ/L²

L² = a² + x² where a = radius of ring and x = distance of axis of ring from sphere.

L = √(a² + x²)

cosФ = x/L

dF' = GmdMcosФ/L²

dF' = GmdMx/L³

dF' = GmdMx/[√(a² + x²)]³

Integrating both sides we have

∫dF' = ∫GmdMx/[√(a² + x²)]³

∫dF' = Gm∫dMx/[√(a² + x²)]³    ∫dM = M

F = GmMx/[√(a² + x²)]³  

F = GMmx/[√(a² + x²)]³

So, the force due to the sphere of mass m is

F = GMmx/[√(a² + x²)]³

3 0
3 years ago
A moving small car has a head-on collision with a large stationary truck 7.3 times the mass of the car. Which statement is true
ad-work [718]
The car bounces off and moves in the opposite direction
8 0
3 years ago
Read 2 more answers
Write a numerical expression for the emissive intensity (in W/m^2.sr) coming out of a tiny hole in an enclosure of surface tempe
stiks02 [169]

Answer:

6.0 × 10^{11} W/m^{2}

Explanation:

From Wien's displacement formula;

Q = e AT^{4}

Where: Q is the quantity of heat transferred, e is the emissivity of the surface, A is the area, and T is the temperature.

The emissive intensity = \frac{Q}{A} = eT^{4}

Given from the question that: e = 0.6 and T = 1000K, thus;

emissive intensity = 0.6 × (1000)^{4}

                             = 0.6 × 1.0 × 10^{12}

                             = 6.0 × 10^{11} \frac{W}{m^{2} }

Therefore, the emissive intensity coming out of the surface is 6.0 × 10^{11} W/m^{2}.

3 0
3 years ago
Walt ran 5 km in 25 minutes going east to what was his average velocity
goldenfox [79]

distance d = 5 km = 5 x 1000 m = 5000 m

time taken = 25 minute = 25 x 60 sec = 1500 sec

average velocity V = d/t

V = 5000/1500

V = 3.33 m/s towards east

3 0
4 years ago
Read 2 more answers
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