Answer:
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Explanation:
The new volume : V₂ = 2454.8 L
<h3>Further explanation</h3>
Given
V₁=2240 L
P₁=760 mmHg
T₁=320 K
P₂=700 mmHg
T₂=323 K
Required
Volume V₂
Solution
Combined gas law :
P₁V₁/T₁=P₂V₂/T₂
Input the value :
760 mmHg x 2240 L /320 K = 700 mmHg x V₂/323 K
V₂=(P₁V₁T₂)/P₂T₁
V₂=(760 x 2240 x 323)/(700 x 320)
V₂ = 2454.8 L
Answer is (b)
2,3,1 is the stoichiometry
The values in front of the elements are the stoichiometric values
(Since Al2Br6 has no value in front, it's considered 1)
The volume of 0. 250 mole sample of gas occupy if it had a pressure of 1. 70 atm and a temperature of 35 °C is 3.71 L.
Calculation,
According to ideal gas equation which is known as ideal gas law,
PV =n RT
- P is the pressure of the hydrogen gas = 1.7 atm
- Vis the volume of the hydrogen gas = ?
- n is the number of the hydrogen gas = 0.25 mole
- R is the universal gas constant = 0.082 atm L/mole K
- T is the temperature of the sample = 35°C = 35 + 273 = 308 K
By putting all the values of the given data like pressure temperature universal gas constant and number of moles in equation (i) we get ,
1.7 atm×V = 0.25 mole ×0.082 × 208 K
V = 0.25 mole ×0.082atm L /mole K × 308 K /1.7 atm
V = 3.71 L
So, volume of the sample of the hydrogen gas occupy is 3.71 L.
learn more about ideal gas equation
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