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Liono4ka [1.6K]
3 years ago
9

If a sloth is traveling at its top speed of 0.067 m/s (0.15 mph), how long does it take the sloth to travel a 11.5 meter tree?

Chemistry
2 answers:
MakcuM [25]3 years ago
8 0

Answer:

17 mins

Explanation:

its 17 mins

marishachu [46]3 years ago
7 0
I think the answer is a: 17mins
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Explain the first three steps of scientific inquiry
erastovalidia [21]
1. Observation-- making observations and taking notes about what you see, smell, hear, think, etc.
2. Question-- developing a question to test your observations.
3. Hypothesis-- creating an educated guess as to the answer of your question.
5 0
3 years ago
A sample of 23.2 g of nitrogen gas is reacted with
slavikrds [6]

Answer:

1.66 moles.

Explanation:

We'll begin by calculating the number of mole in 23.2 g of nitrogen gas, N2.

This is illustrated below:

Molar mass of N2 = 2x14 = 28 g/mol

Mass of N2 = 23.2 g

Mole of N2 =.?

Mole = mass /Molar mass

Mole of N2 = 23.2/28

Mole of N2 = 0.83 mole

Next, we shall determine the number of mole in 23.2 g of Hydrogen gas, H2.

This is illustrated below:

Molar mass of H2 = 2x1 = 2 g/mol

Mass of H2 = 23.2 g

Mole of H2 =?

Mole = mass /Molar mass

Mole of H2 = 23.2/2

Mole of H2 = 11.6 moles

Next, the balanced equation for the reaction. This is given below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2.

Therefore, 0.83 moles will react with = (0.83 x 3) = 2.49 moles of H2.

From the calculations made above, we can see that only 2.49 moles out of 11.6 moles of H2 is required to react completely with 0.83 mole of N2.

Therefore, N2 is the limiting reactant.

Finally, we shall determine the maximum amount of NH3 produced from the reaction.

In this case, we shall use the limiting reactant because it will give the maximum yield of NH3 since all of it is consumed in the reaction.

The limiting reactant is N2 and the maximum amount of NH3 produced can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 0.83 mole of N2 will react to produce = (0.83 x 2) = 1.66 moles of NH3.

Therefore, the maximum amount of NH3 produced from the reaction is 1.66 moles.

5 0
3 years ago
When magnesium reacts with hydrochloric acid, hydrogen gas is produced. The amount of gas produced is dependent upon the concent
velikii [3]

Answer:

why do you need human rights ! write in a sentence

7 0
2 years ago
Help me please i'm begging you its DUE today its super easy
NARA [144]

Answer:

The answer will be listed below.

Explanation:

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6 0
3 years ago
The chemist discovers a more efficient catalyst that can produce ethyl butyrate with a 78.0% yield. How many grams would be prod
Vedmedyk [2.9K]

The grams that would be produced  from 7.70 g of butanoic acid and excess ethanol is 7.923grams

calculation

Step 1: write the chemical equation for the reaction

CH3CH2CH2COOH + CH3CH2OH →  CH3CH2CH2COOCH2CH3  +H2O

step 2: find the moles of butanoic acid

moles= mass/ molar mass

=  7.70 g/ 88 g/mol=0.0875 moles

Step 3:  use the mole ratio to determine the moles of ethyl butyrate

moles ratio of CH3CH2CH2COOH :CH3CH2CH2COOCH2CH3  is 1:1 therefore the moles of CH3CH2CH2COOCH2CH3 = 0.0875  x78/100=0.0683moles

step 4: find mass = moles x molar mass

 =  0.0683 moles  x116 g/mol=7.923grams

5 0
3 years ago
Read 2 more answers
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