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Anvisha [2.4K]
3 years ago
11

An estimate for -93 is.

Mathematics
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

-90

Step-by-step explanation:

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Explain why P(A|D) and P(D|A) from the table below are not equal.
trasher [3.6K]

Answer:

The Probability that Event A and  Event D occur is equal to the probability Event A occurs times the probability that Event D occurs, given that A has occurred.


P(A\cap D)=P(A)\cdot P(D/A)

We can find the values of P(A/D) and P(D/A) using the above form formula.

P(D/A)=\frac{P(A\cap D)}{P(A)} ;

P(A/D)=\frac{P(D\cap A)}{P(D)}

From the given table, we have the values of P(A), P(D), P(D\cap A) and P(A\cap D).

Since, Probability=\frac{The number of wanted outcomes }{the number of possible outcomes}

∴P(A)=\frac{8}{17}, P(D)=\frac{10}{17}, P(A\cap D)=\frac{2}{17} and P(D\cap A)=\frac{2}{17}

Now, putting these values in above formula we get,

P(D/A)=\frac{\frac{2}{17}} {\frac{8}{17}}

P(D/A)=\frac{2} {8}=\frac{1}{4}

P(D/A)= \frac{1}{4}.

P(A/D)=\frac{\frac{2}{17}} {\frac{10}{17}}=\frac{2}{10}

P(A/D)=\frac{1}{5}

As, you can see above that the values of P(A|D) and P(D|A) are not equal.









5 0
3 years ago
Read 2 more answers
A job fair was held at the Student Union. 25% of the students who attended received job offers. Of all of the students at the jo
vovangra [49]

Answer:

A) Both events are not independent.

B) Both events are not mutually exclusive

C) 8.33%

D) 80%

Step-by-step explanation:

A) Both events are not independent. This is because, If B occurs it means that it is very likely that J will occur as well.

B) Both events are not mutually exclusive. This is because it is possible for both events J and B to occur at the same time.

C) we want to find the probability that Joe who is not a business student will receive the job offer.

This is;

P(J|Not B) = P(J & Not B)/P(Not B)

Now,

P(J & Not B) = P(J) – (P(B) × P(J | B))

25% of the students who attended received job offers. Thus; P(J) = 0.25

40% were from the College of Business. Thus;

P(B) = 0.4

Among the business students, 50% received job offers. Thus;

P(J|B) = 0.5

Thus;

P(J & Not B) = 0.25 - (0.4 × 0.5)

P(J & Not B) = 0.25 - 0.2

P(J & Not B) = 0.05

Since P(B) = 0.4

Then, P(Not B) = 1 - 0.4 = 0.6

Thus;

P(J|Not B) = 0.05/0.6

P(J|Not B) = 0.0833 = 8.33%

D) This probability is represented by;

P(B | J) = P(B & J)/P(J)

P(B & J) = (P(B) × P(J | B)) = (0.4 × 0.5) = 0.2

P(B | J) = 0.2/0.25

P(B | J) = 0.8 = 80%

5 0
3 years ago
Please help me ill give you 10 points
Kitty [74]
C=2pi8
c=16pi or c≈50.27
7 0
3 years ago
Using a graph, table of values, and/or equations solve the following problem.
olchik [2.2K]

Answer:

n = 11/3

Step-by-step explanation:

n = certain number

6n - 1 = 21

6n = 22

n = 22/6 or 11/3

3 0
3 years ago
Select ALL of the choices that are equal to (-2) - (-5)
saveliy_v [14]
(-2)+(-5) ok ok have a good day
5 0
3 years ago
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