Answer:
Explanation:
The number of moles of solute is equal to product of the molar concentration (molarity) and the volume (in liters) of solution.
Since the volumes and the molar concentrations of the<em> NaOH </em>and <em>HCl </em>solutions mixed are equal, each one of them contributes the same number of moles of solute.
Since every mol of NaOH produces one mol of OH⁻ ions and every mol of HCl produces one mol of H⁺ ion, the number of moles of OH ⁻ and H⁺ in solution are equal.
Thus, OH⁻ and H⁺ ions will be neutralized by the reaction:
- OH⁻ (aq) + H⁺ (aq) ⇄ H₂O (l)
Which is strongly shifted to the right and has <em>neutral pH</em>.
Hence, you conclude that the approximate <em>pH of the solution is neutral.</em>
Answer:
c
Explanation:
hydrogen Bond exist between ammoia, hydrogen fluoride and water so the answer is c
Answer: No I+ cannot be called a Lewis base.
Explanation:
According to Lewis Theory, it defines an acid as an electron-pair acceptor and a base as an electron-pair donor.
In terms of Lewis basicity, Iodide ion (anions) has the more readily available lone pair electrons for donation since iodide ion is less electronegative .
With the help of the net electronic structure one can understand the answer of the question, because we need to study the I+ ion (cation) structure.
Lewis acid is therefore any substance, that can accept a pair of nonbonding electrons.
From the picture below I+ is most likely ready to accept electrons not to give from it 5s orbital to become stable.
Answer:
the correct name is London international animation festival
Explanation:
Answer:
600k
Explanation:
In this problem, we need to use a gas law that relates temperature to volume. The gas law to use here is the Charles’ law.
The Charles’ law posits that temperature and volume are directly proportional, provided that the pressure is kept constant.
Mathematically:
V1/T1 = V2/T2
We are looking at getting V2, hence we can write the mathematical equation as:
T2 = V2T1/V1
Asides the fact that we know that the gas is monoatomic, we do not know its volume. Let its initial volume be v. Since it expanded adiabatically, this means that its new volume is 2v
Hence: V1 = v , V2 = 2v , T1 = 300k and T2 is ?
Substituting these values, we have the following:
T2 = (2v * 300)/v
T2 = 600k
