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4 years ago

6. Identify the number of neutrons in one atom of silicon with an isotopic mass number of 28 amu.

Chemistry

1 answer:

Sholpan [36]4 years ago

5 0

Explanation:

The number of neutrons in one atom of silicon with an isotopic mass number of 28amu is 14.

An atom is made up three fundamental sub-atomic particles which are:

Protons, neutron and electrons

Protons are the positively charged particles in an atom

Neutrons do not carry any charges

Electrons are the negatively charged particles.

In the nucleus of an atom, both protons and neutrons can be found. They are the massive particle in an atom.

The mass number of an atom = number of protons + number of neutrons

Number of neutrons = mass number - number of protons.

From the periodic table, we know that silicon has an atomic number of 14.

The atomic number is the number of protons in an atom:

Number of neutrons = 28 - 14 = 14amu

In the atom, we will have 14amu of neutrons in a silicon atom.

learn more:

Number of neutrons brainly.com/question/2757829

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25. Compare the compositions of binary ionic and binary molecular compounds. 26. Write the general chemical formula for an acid,

Murljashka [212]

Explanation:

25. Binary ionic compounds: They are known as the compounds which contains a cation formed from a metal and an anion formed from a non-metal or a polyatomic anion. For example : Barium sulfate

Ba : +2 ( metal of group II-A)

$SO_4$ : -2 ( sulfate)

These two ions combine to form a binary ionic compound having formula $BaSO_4$

Binary Molecular compounds: They are known as the compounds which contain two or more non-metals that are bonded covalently. In these compounds, no ions are present because the electrons are shared by the atoms. Examples are: $PCl_3$ : phosphorous trichloride

$SO_2$ : sulfur dioxide

26. The general chemical formula for an acid is HX where H is the hydrogen and X is the non-metal or polyatomic ions. Examples of acids are:

HF : Hydrofluoric acid

$H_2SO_4$ : Sulfuric acid

5 0

4 years ago

Read 2 more answers

A solution contains 1 LaTeX: \times\:×10−4 M OH– ions. Calculate the solution pH value, and determine if the solution is acidic,

docker41 [41]

Answer:

pH = 10

The solution is basic.

Explanation:

A solution contains 1 × 10⁻⁴ M OH⁻ ions. First, we will calculate the pOH.

pOH = -log [OH⁻]

pOH = -log 1 × 10⁻⁴

pOH = 4

We can find the pH of the solution using the following expression.

pH + pOH = 14.00

pH = 14.00 - pOH = 14.00 - 4 = 10

Since the pH > 7, the solution is basic.

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4 years ago

What is true about a solution of 1.0 M HF?

DanielleElmas [232]

Hydrofluoric acid is not a strong acid despite being a hydrohaulic acid (hydrogen and a halogen). HF is highly corrosive and can be used to dissolve most oxides

7 0

3 years ago

Which of the following would be part of an aquatic ecosystem?

Masja [62]

Answer:

Aquatic ecosystem has two components -

Biotic components

2.Abiotic components

temperature and amount of sunlight are the part of abiotic component .

while living things like sponges and planktons are the biotic components of ecosystem.

Explanation:

aquatic components are of two types-

freshwater ecosystem( lakes and ponds, river and streams)

marine ecosystem(ocean ecosysyem, estuaries)

planktons-

planktons are found in limnetic zone, availability of sunlight is much here. planktons are zooplanktons and phytoplanktons are very important link in aquatic ecosystem.

sponges

In marine water, the benthic zone is the area below the pelagic zone. Here temperature decreased because of less light perception. This zone is very nutrient rich so organisms which are present here are- bacteria, fungi, sea anemone, sponges and some fishes.

3 0

3 years ago

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Tim wants to store 0.122 moles of helium gas at 203 kPa and 401 K. Which is the volume of the helium gas needed for storage?

algol13

The volume of Helium gas needed for storage is 2.00 L (answer C)

calculation

The volume of Helium is calculated using ideal gas equation

That is Pv =nRT

where;

P( pressure) = 203 KPa

V(volume)=?

n(number of moles) = 0.122 moles

R(gas constant) = 8.314 L.Kpa/mol.K

T(temperature)= 401 K

make V the subject of the formula by diving both side by P

V=nRT/p

V={[0.122 moles x 8.314 L. KPa/mol.K x 401 K] / 203 KPa} = 2.00 L

3 0

3 years ago