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andreev551 [17]
3 years ago
10

Which of the following statements is true for an exothermic reaction?

Chemistry
2 answers:
shutvik [7]3 years ago
6 0
The enthalpy change for an exothermic reaction is negative because heat is being released, so that takes out two of the responses. Since energy is being released into the surroundings due to the exothermic reaction, the potential energy of the products is lower than that of the reactants. Energy is being put in to make the reaction occur, but then that energy is all being released into the surroundings thus a lower potential energy level for the products
Natalija [7]3 years ago
5 0

<u>Ans: The products have lower potential energy than the reactants, and the enthalpy change is negative. </u>

In general, chemical reactions can be broadly classified into two categories:

1) Exothermic

2) Endothermic

Exothermic reactions proceed with the evolution of heat. Here, the reactants have a higher potential energy which is released as the reaction progresses to form products. Consequently, the products are in a lower energy state. Since energy is released, the enthalpy change will be negative.

In contrast, endothermic reactions proceed with the absorption of heat. Here,the products will be in a higher energy state. Since energy is absorbed, the enthalpy change will be positive.

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As specific gravity is defined as weight per unit volume,so urine is the less dense fluid,so urine will be in hyperosmotic category.

8 0
3 years ago
Given a magnesium value of 4.5mg/dL, what is the result in SI units?
DaniilM [7]

Answer:

4.5x10^{-5}\frac{kg}{L}

Explanation:

Hello!

In this case, since the density in the international system of units is given in terms of kg for the mass and L for the volume, we need to perform a process of units conversions from mg and dL to kg and L as show below:

4.5\frac{mg}d{L}*\frac{1kg}{1x10^6mg}  *\frac{10dL}{1L} \\\\4.5x10^{-5}\frac{kg}{L}

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3 years ago
The first-order rate constant for the decomposition of N2O5:
kifflom [539]

Answer:

0.0055 mol of N2O5 will remay after 7 min.

Explanation:

The reaction follows a first-order.

Let the concentration of N2O5 after 7 min be y

Rate = Ky = change in concentration of N2O5/time

K is rate constant = 6.82×10^-3 s^-1

Initial concentration of N2O5 = number of moles/volume = 2.1×10^-2/1.8 = 0.0117 M

Change in concentration = 0.0117 - y

Time = 7 min = 7×60 = 420 s

6.82×10^-3y = 0.0117 - y/420

0.0117 - y = 420×6.82×10^-3y

0.0117 - y = 2.8644y

0.0117 = 2.8644y + y

0.0117 = 3.8644y

y = 0.0117/3.8644 = 0.00303 M

Number of moles of N2O5 left = y × volume = 0.00303 × 1.8 = 0.0055 mol (to 2 significant digits)

5 0
3 years ago
A sample of barium nitrate is placed into a jar containing water. The mass of the barium nitrate sample is 27g. Assume the water
34kurt
So we have Barium nitrate with a solubility of 8.7g in 100g water at 20°C.

using that relation
i.e.
8.7g (barium nitrate) =100g (water)
1g barium nitrate = 100/8.7 g water

27g barium nitrate = (100/ 8.7 ) × 27
= 310.34 g

therefore,
you need 310.34g of water is in the jar.

5 0
3 years ago
Read 2 more answers
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