Answer:
200.00 mol
Explanation:
Nitric acid: Nitrogen dioxide is 2:3
and nitrogen dioxide is already 300.00 mol so using the ratio, nitric acid is 200.00 mol
The correct answer is "apply heat". A <span>method that will speed up a chemical reaction is to apply heat. Energy is directly proportional to kinetic energy which is the energy of motion. Increasing the heat will promote the molecules to move faster therefore colliding more to the molecules in the system resulting to a faster reaction.</span>
Answer:
Explanation:
A compound must have a net charge of 0. The charges have to balance each other out and equal 0.
We have the compound sulfur trioxide with a chemical formula of SO₃.
Oxygen (O) has an oxidation state of -2, which means it will have a charge of -2 in the compound. However, note there is a subscript after the O in the chemical formula. Therefore, there are 3 oxygen atoms in the compound and each one has a charge of -2. The oxygen has an overall charge of -6 because 3*-2 = -6.
There is only one atom of sulfur (there is no subscript, so a 1 is implied). It has to balance out the -6 charge of the oxygen atoms, so it must be +6.
The oxidation number for sulfur is +6 in the compound sulfur trioxide.
The correct answer would be A i think hope it helps
Answer:
8.934 g
Step-by-step explanation:
We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 192.12 44.01
H₃C₆H₅O₇ + 3NaHCO₃ ⟶ Na₃C₆H₅O₇ + 3H₂O + 3CO₂
m/g: 13.00
For ease of writing, let's write H₃C₆H₅O₇ as H₃Cit.
(a) Calculate the <em>moles of H₃Cit
</em>
n = 13.00 g × (1 mol H₃Cit /192.12 g H₃Cit)
n = 0.067 67 mol H₃Cit
(b) Calculate the <em>moles of CO₂
</em>
The molar ratio is (3 mol CO₂/1 mol H₃Cit)
n = 0.067 67 mol H₃Cit × (3 mol CO₂/1 mol H₃Cit)
n = 0.2030 mol CO₂
(c) Calculate the <em>mass of CO₂
</em>
m = 0.2030 mol CO₂ × (44.01 g CO₂/1 mol CO₂)
m = 8.934 g CO₂