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3 years ago

What effect does earths tilt have on the planet

Chemistry

1 answer:

Alexeev081 [22]3 years ago

7 0

The seasons are caused as the earth, tilted on its axis, travels in a loop around the sun each year

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Complete the sentence: The greater the force that is applied to an object, the _____ the acceleration. However, if that same for

Alla [95]

Answer:

The greater the force that is applied to an object, the greater the acceleration. However, if that same force was applied to an object with a larger mass, it will have a smaller acceleration.

Explanation:

f=ma

7 0

3 years ago

Read 2 more answers

The substance reduced in a hydrogen-oxygen fuel cell is _____. oxygen hydrogen water hydrogen peroxide\

S_A_V [24]

Answer: Oxygen

Explanation:

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3 years ago

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2AlF3 + 3K2O → 6KF + Al2O3

Agata [3.3K]

<h3>Answer:</h3>

7.4797 g AlF₃

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

Reading a Periodic Table
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN] 2AlF₃ + 3K₂O → 6KF + Al₂O₃

[Given] 15.524 g KF

<u>Step 2: Identify Conversions</u>

[RxN] 6 mol KF = 2 mol AlF₃

Molar Mass of K - 39.10 g/mol

Molar Mass of F - 19.00 g/mol

Molar Mass of Al - 26.98 g/mol

Molar Mass of KF - 39.10 + 19.00 = 58.1 g/mol

Molar Mass of AlF₃ - 26.98 + 3(19.00) = 83.98 g/mol

<u>Step 3: Stoichiometry</u>

Set up: $\displaystyle 15.524 \ g \ KF(\frac{1 \ mol \ KF}{58.1 \ g \ KF})(\frac{2 \ mol \ AlF_3}{6 \ mol \ KF})(\frac{83.98 \ g \ AlF_3}{1 \ mol \ AlF_3})$
Multiply/Divide: $\displaystyle 7.47966 \ g \ AlF_3$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 5 sig figs.</em>

7.47966 g AlF₃ ≈ 7.4797 g AlF₃

3 0

3 years ago

Write a balanced equilibrium equation for the dissolution of nai in water. include phases.

Bess [88]

Dissolution means to make the compound apart, So when we have ionic compounds like NaI which has metal and non-metal ions, It separates into parts of positive ions and negative ions. After we separate this compound apart we will put the charge of each on above its symbol and then start to balance the equation of the dissolution.

So the dissolution equation of NaI is:
NaI(s) → Na^+(s) + I^-(Aqu)

3 0

3 years ago

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Determine the mass percent composition of a solution made by dissolving 40.1g of LiOH in 681g of H2O

Lapatulllka [165]

<h3>Answer:</h3>

5.89%

<h3>Explanation:</h3>

We are given;

Mass of the solute, LiOH as 40.1 g
Mass of the solvent, H₂O as 681 g

We are required to calculate the mass percent composition of solution;

But; How do we calculate the mass percent composition of a solution?
We use the formula;

Mass composition of a solution = (Mass of solute/mass of solution) 100%

Therefore;

Mass Percent = (40.1 g/681 g)× 100%

= 5.888 %

= 5.89%

Therefore, the mass percent composition of the solution is 5.89%

7 0

3 years ago