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k0ka [10]
3 years ago
6

A certain drug is made from only two ingredients: compound A and compound B. There are 3 milliliters of compound A used for ever

y 4 milliliters of compound B. If a chemist wants to make 533 milliliters of the drug, how many milliliters of compound B are needed?
Mathematics
2 answers:
Sphinxa [80]3 years ago
5 0

Answer:

304\dfrac{4}{7}\ milliliters

Step-by-step explanation:

If there are 3 milliliters of compound A used for every 4 milliliters of compound B, then we can denote that we use 3x milliliters of compound A and 4x milliliters of compound B to get 533 milliliters of the drug. Thus,

3x+4x=533,\\ \\7x=533,\\ \\x=\dfrac{533}{7}\ milliliters.

Hence, a chemist must take

4\cdot \dfrac{533}{7}=\dfrac{2132}{7}=304\dfrac{4}{7}\ milliliters

of compound B.

Basile [38]3 years ago
3 0

Answer:

228.43 ml

Step-by-step explanation:

The ratio of compound A to compound B will be; 4: 3

4:3 is the same as 4x:3x where 4x is compound A and 3x is compound B.

We can solve for "x":

If amount of compound A is 4x  and compound B is 3x;

Then; 4x + 3x = 533

            7 x = 533

               x = 533/7

Then amount of compound B is 3x = 3(533/7)

                                                          = 228.43 ml

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If f(1) = 10 and f(n) = f(n = 1) – 4 then find the value of f(5).
svetoff [14.1K]

Given:

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To find:

The value of f(5).

Solution:

We have,

f(n)=f(n-1)-4

For n=2,

f(2)=f(2-1)-4

f(2)=f(1)-4

f(2)=10-4

f(2)=6

For n=3,

f(3)=f(3-1)-4

f(3)=f(2)-4

f(3)=6-4

f(3)=2

For n=4,

f(4)=f(4-1)-4

f(4)=f(3)-4

f(4)=2-4

f(4)=-2

For n=5,

f(5)=f(5-1)-4

f(5)=f(4)-4

f(5)=-2-4

f(5)=-6

Therefore, the value of f(5) is -6.

5 0
3 years ago
Changing Bases to Evaluate Logarithms in Exercise, use the change-of-base formula and a calculator to evaluate the logarithm. Se
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Answer:

Log_5 12=1.54

Step-by-step explanation:

We are given that

Log_5 12

We have to find the value of given logarithms by using change-base formula

Base-change formula:

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Where x=New base

Using the formula then, we get

Log_5 12=\frac{log_{10} 12}{log_{10} 5}

Substitute the values log_{10}12=1.079, log_{10}5=0.699

Then,we get

Log_5 12=\frac{1.079}{0.699}

Log_5 12=1.54

3 0
3 years ago
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