Question

PLEASE ANSWER!!! You are helping wish some repairs at home. you drop a hammer and it hits the floor at a speed of 12 feet per second. If the acceleration due to gravity (g) is 32 feet/second², how far above the ground (h) was the hammer when you dropped it? Use the formula: v=√2gh A. 2.25 feet B. 18.0 feet C. 8.5 feet D. 1.0 foot

Answer 1

Answer:

h = 2.25 m

Step-by-step explanation:

Given:

Speed = v = 12 ft/sec

Acceleration due to gravity = g = 32 ft/sec²

Required:

Height = h = ?

Formula:

v = $\sqrt{2gh}$

Solution:

For h, the formula will be:

=> h = $\frac{v^2}{2g}$

=> h = $\frac{(12)^2}{2(32)}$

=> h = $\frac{144}{64}$

=> h = 2.25 m