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Len [333]
3 years ago
8

PLEASE ANSWER!!! You are helping wish some repairs at home. you drop a hammer and it hits the floor at a speed of 12 feet per se

cond. If the acceleration due to gravity (g) is 32 feet/second², how far above the ground (h) was the hammer when you dropped it? Use the formula: v=√2gh A. 2.25 feet B. 18.0 feet C. 8.5 feet D. 1.0 foot
Mathematics
1 answer:
Andru [333]3 years ago
8 0

Answer:

h = 2.25 m

Step-by-step explanation:

<u><em>Given:</em></u>

Speed = v = 12 ft/sec

Acceleration due to gravity = g = 32 ft/sec²

<u><em>Required:</em></u>

Height = h = ?

<u><em>Formula:</em></u>

v = \sqrt{2gh}

<u><em>Solution:</em></u>

For h, the formula will be:

=> h = \frac{v^2}{2g}

=> h = \frac{(12)^2}{2(32)}

=> h = \frac{144}{64}

=> h = 2.25 m

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