Order from lease to greatest: 5/6, 4/5, 0.82?
1 answer:
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Answer:
a) 56.67% probability that the student is a woman
b) 16.67% probability that the student received an A
c) 63.33% probability that the student is a woman or received an A.
d) 83.33% probability that the student did not receive an A.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
We have that:
30 students
13 men
17 women
2 men that got an A and 11 men that did not get an A.
3 women that got an A and 14 women that did not get an A.
a. Find the probability that the student is a woman.
30 students, of which 17 are women.
56.67% probability that the student is a woman
b. Find the probability that the student received an A.
30 students, of which 5 received an A
16.67% probability that the student received an A
c. Find the probability that the student is a woman or received an A.
30 students, of which 17 are women and 2 are men who received an A. So
63.33% probability that the student is a woman or received an A.
d. Find the probability that the student did not receive an A.
30 students, of which 25 did not receive an A.
83.33% probability that the student did not receive an A.
Answer:
The 95% confidence interval for the difference between the Route B and Route A commuting times is -3.771808 to 1.771808
Step-by-step explanation:
Here we have the confidence interval is given by the following equation;
= 49 Minutes
σ₁ = 2 Minutes
= 50 Minutes
σ₂ = 4 Minutes
n₁ = n₂ = 10 days
α = 0.05
At 95%, from the z score table , z =
1.959964 ≈ ± 1.96
Plugging in the values Solving we get
Δμ Min = -3.771808 and Δμ Max = 1.771808.