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earnstyle [38]
3 years ago
14

Loan A (bank) requires a total payback of $54,289.44 while Loan B (dealership) requires a total payback of $55,098.60.

Mathematics
1 answer:
dedylja [7]3 years ago
8 0

Answer: Loan B requires more interest by $809.16.

Step-by-step explanation:

Subtract the total pay back of loan B from loan A

= $55,098.60 - $54,289.44

= $809.16

I hope this helps, please mark as brainliest answer.

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Who knows how to do this please i need help I don’t understand
ArbitrLikvidat [17]

Answer:

9,4,0,1

Step-by-step explanation:

They give you different values for the X so all you have to do is plug in the X to the different equations

3 0
3 years ago
Shadily softball team has a phone tree in case the game is canceled the coach calls three players then each of those players cal
irga5000 [103]

Answer: 27 players will be notified during the third round of calls.

Step-by-step explanation:

In case the game is canceled, the coach calls three players. This means that if each of these three players call three more players, the number of players that will be notified during second round of call would be

3 × 3 = 9 players.

If each of these nine players call three more players, the number of players that will be notified during third round of call would be

9 × 3 = 27 players.

The total number of players that would have been notified is

3 + 9 + 27 = 39 players

3 0
3 years ago
Simplify
fiasKO [112]
The answer is d have a nice day
8 0
3 years ago
Read 2 more answers
Ten feet below sea level is farther below sea level than 2 and a half feet below sea level
bulgar [2K]

Answer:

correct

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were​ born
strojnjashka [21]

Answer:

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 335, \pi = \frac{268}{335} = 0.8

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563

For the percentage:

Multiplying the proportions by 100.

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0
3 years ago
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