<em>i</em><em> </em><em>think</em><em> </em><em>it</em><em> </em><em>is</em><em><u> </u></em><em><u>8</u></em>
Step-by-step explanation:
hope this helps! ;)
Answer:
8,000 in the 8% account
20,000 in the 9% account.
Step-by-step explanation:
x + y = 28000
0.08 x + 0.09 y = 2440
0.08 x + 0.09 (28000 − x) = 2440
0.08 x + 2520 − 0.09 x = 2440
80 = 0.01 x
x = 8000
y = 20000
<span>Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral.
Let's see now, Delmar has a line segment WX and has drawn 2 circles whose radius is the length of WX, centered upon W and centered upon X. Sounds to me that all he needs to do is select one of the intersections of those 2 circles and use that at the 3rd point of the equilateral triangle and draw a line from that point to W and another line from that point to X. Doesn't matter which of the two intersections he chooses, just needs to pick one. Looking at the available options, only the 1st one which is "Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral." matches my description, so that is the correct choice. The other choices tend to do rather bizarre things like create a perpendicular bisector of WX and for some unknown reason, claim that bisector is somehow a side of a desired equilateral triangle.</span>
Answer : P(second resistor is 100ω , given that the first resistor is 50ω) is given by
Explanation :
Since we have given that
Total number of resistors =15
Number of resistors labelled with 50ω = 12
Number of resistors labelled with 100ω =3
Let A: Event getting resistor with 50ω
B: Event getting resistor with 100ω
Since A and B are independent events .
So,
Now, According to question , we can get that
So,
So, by using the conditional probability , which state that
So, P(second resistor is 100ω , given that the first resistor is 50ω) is given by
