Answer:
Products are AgBr and KNO3
Stoichiometry <span>of the reaction:
</span><span>2 KClO</span>₃<span> = 2 KCl + 3 O</span>₂
↓ ↓
2 mole KClO₃ ----------> 3 mole O₂
2 mole KClO₃ ----------> ?
KClO₃ = 2 * 3 / 2
KClO₃ = 6 / 2
= 3 moles de KClO₃
hope this helps!
Answer:
Change in internal energy (ΔU) = -9 KJ
Explanation:
Given:
q = –8 kJ [Heat removed]
w = –1 kJ [Work done]
Find:
Change in internal energy (ΔU)
Computation:
Change in internal energy (ΔU) = q + w
Change in internal energy (ΔU) = -8 KJ + (-1 KJ)
Change in internal energy (ΔU) = -8 KJ - 1 KJ
Change in internal energy (ΔU) = -9 KJ
In chemistry and atomic physics, the main group is the group of elements whose lightest members are represented by helium, lithium, beryllium, boron, carbon, nitrogen, oxygen, and fluorine as arranged in the periodic table of the elements
