1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
USPshnik [31]
1 year ago
5

If the decomposition of a sample of k c l o 3 kclox3 produces 3. 29 g of o 2 ox2 , what was the mass (g) of the original sample?

Chemistry
1 answer:
____ [38]1 year ago
5 0

The mass (g) of the original sample after decomposition is 8.3983 g.

A decomposition reaction can be described as a chemical reaction wherein one reactant breaks down into or extra merchandise.

explanation:

Reaction          2KClO₃ ⇒ 2KCl + 3O₂

moles               2               2            3

molar mass    122.55        74.55    32

Given, Mass of O₂ = 3.29g ⇒ moles of O₂

                                            =  (3.29/32) = 0.1028

3 moles of O₂  produced by 2 moles of KClO₃

Therefore, 0.1028 moles of O₂  produced by (2*0.1028/3) = 0.06853 moles of Kclo₃

Mass of KClo₃ in original sample is = moles * molar mass

                                                        = 0.06853 * 122.55

                                                       = 8.3983 g

A decomposition response occurs whilst one reactant breaks down into or extra merchandise. this may be represented through the general equation: XY → X+ Y. Examples of decomposition reactions consist of the breakdown of hydrogen peroxide to water and oxygen, and the breakdown of water to hydrogen and oxygen.

Learn more about decomposition here:-brainly.com/question/27300160

#SPJ4

You might be interested in
is carried out adiabatically in a constant-volume batch reactor. The rate law is Plot and analyze the conversion, temperature, a
Sphinxa [80]

Answer:

See explaination

Explanation:

The mole balance for a constant-volume batch reactor is given such as, For a first-order isothermal reaction, the time to reach a given conversion is the same for constant-pressure and constant-volume reactors. Also, the time is the same for a reaction of any order if there is no change in the number of moles.

Please kindly check attachment for the step by step solution of the given problem.

5 0
3 years ago
I WILL MARK BRAINLISET FOR WHOEVER GETS THIS RIGHT! A pot is placed on a gas flame, and the water inside the pot begins to boil.
NNADVOKAT [17]

Answer:

B.     Warm water rises within the pot.?

Explanation

<em>There wasn't enough information given for me to safely determine the correct answer.</em>

8 0
3 years ago
Which protists lack cilia and flagella, but can still move around?
timama [110]

Answer: amoebae !

Explanation:

3 0
3 years ago
What category is most of the elements part of
rjkz [21]

Answer:

transition metals

Explanation:

they're the elements in yellow in the picture

6 0
2 years ago
When a nonmetal bonds with a nonmetal, they form a(n)
seropon [69]
Covalent bonds would be formed when a non-metal bonds with another non-metal 
6 0
3 years ago
Other questions:
  • Helium gas has a molar mass of 4 g/mol. oxygen gas has a molar mass of 32 g/mol. how much faster or slower would helium effuse t
    9·1 answer
  • How should the table be changed to correctly distinguish between mechanical and electromagnetic waves?
    9·2 answers
  • How many electrons does (Al) have to give up to achieve a noble gas?
    5·1 answer
  • Glucose, C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the equation
    5·1 answer
  • What is a single<br> replacement rxn?
    7·1 answer
  • Convert the pressure 1.30 atm to kPa
    14·1 answer
  • When will Le Chatelier's principle come into effect?
    7·1 answer
  • The gas formed when coal is heated in the absence of air_____________
    8·1 answer
  • Which element is the most<br> reactive element in group one of the periodic<br> table
    12·1 answer
  • A)
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!