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2 years ago

Gina ate 3/4 of an apple pie. greg ate 1/8 of the same pie. how much of the Apple pie was left?

1 answer:

5 0

There would be 1/8 of the pie left,
you have to add 3/4 and 1/8 to find the total eaten and then subtract it by 8/8 (the total) which would give you your answer.

Hope it helps

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The equation 7×+1=4×+10 ?

HACTEHA [7]

7x-4x=10-1
3x=9
3/3x=9/3
x=3

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3 years ago

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Determine the kinetic energy of a 100-kg roller coaster car that is moving with a speed of 20.0/ms.

rjkz [21]

Answer:

The kinetic energy is 20,000\ J

Step-by-step explanation:

The kinetic energy of a body is defined as:

$k = \frac{1}{2}ms ^ 2$

Where m is the mass of the roller coaster car

s is the speed and k is the kinetic energy

We know that $s = 20\ m/s$

$m = 100\ kg$

Then the kinetic energy of the roller coaster car is:

$k = \frac{1}{2}(100)(20) ^ 2\\\\k = 50(20) ^ 2\\\\k = 50 * 400\\\\k = 20,000\ J$

3 0

2 years ago

Evaluate the triple integral ∭EzdV where E is the solid bounded by the cylinder y2+z2=81 and the planes x=0,y=9x and z=0 in the

dem82 [27]

Answer:

I = 91.125

Step-by-step explanation:

Given that:

$I = \int \int_E \int zdV$ where E is bounded by the cylinder $y^2 + z^2 = 81$ and the planes x = 0 , y = 9x and z = 0 in the first octant.

The initial activity to carry out is to determine the limits of the region

since curve z = 0 and $y^2 + z^2 = 81$

∴ $z^2 = 81 - y^2$

$z = \sqrt{81 - y^2}$

Thus, z lies between 0 to $\sqrt{81 - y^2}$

GIven curve x = 0 and y = 9x

$x =\dfrac{y}{9}$

As such,x lies between 0 to $\dfrac{y}{9}$

Given curve x = 0 , $x =\dfrac{y}{9}$ and z = 0, $y^2 + z^2 = 81$

y = 0 and

$y^2 = 81 \\ \\ y = \sqrt{81} \\ \\ y = 9$

∴ y lies between 0 and 9

Then $I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \int^{\sqrt{81-y^2}}_{z=0} \ zdzdxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{z^2}{2} \end {bmatrix} ^ {\sqrt {{81-y^2}}}_{0} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{(\sqrt{81 -y^2})^2 }{2}-0 \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{{81 -y^2} }{2} \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81x -xy^2} }{2} \end {bmatrix} ^{\dfrac{y}{9}}_{0} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81(\dfrac{y}{9}) -(\dfrac{y}{9})y^2} }{2}-0 \end {bmatrix} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81 \ y -y^3} }{18} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \int^9_{y=0} \begin {bmatrix} {81 \ y -y^3} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \begin {bmatrix} {81 \ \dfrac{y^2}{2} - \dfrac{y^4}{4}} \end {bmatrix}^9_0$

$I = \dfrac{1}{18} \begin {bmatrix} {40.5 \ (9^2) - \dfrac{9^4}{4}} \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 3280.5 - 1640.25 \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 1640.25 \end {bmatrix}$

I = 91.125

4 0

2 years ago

Meredith is playing games at an arcade to earn tickets that she can exchange for a prize. She has 287 tickets from a previous vi

Zarrin [17]

if y=367

then you need to figure out this:

367=5x+287

so remove 287 from 367

367-287=80

Then divide by 5

80/5=16

so, x=16

4 0

3 years ago

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The local business will donate $5.00 for every 10 tickets sold. Let x represent tickets sold, and y represent dollars donated. S

nydimaria [60]

Answer:

If we let x be the number of ticket sold and y be the amount in dollars donated then, the equation would be,

x = 2y

We can check our answer by substituting the given,

10 = 2(5)

10 = 10

The equation can also be written as,

y = (1/2)x

Student B is correct.

6 0

2 years ago

Read 2 more answers