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romanna [79]
3 years ago
15

Unit 2 Lesson 9: Temperature & Heat Unit Test does anyone have the answers

Physics
2 answers:
IRISSAK [1]3 years ago
8 0

Explanation:

where is the question

I did not understood this question

storchak [24]3 years ago
6 0

Answers:

Here are the answers for the U2L9: Temperature & Heat Unit Test

1. Which describes how radiation moves?

  B) Radiation moves from a warmer object to a cooler object

2. Which material most likely gets warmer when places in the Sun?

  C) brown mulch

3. A thermogram of a house shows high amounts of thermal energy around the windows but not around the roof. Which conclusion is best supported by the thermogram?

  C) The windows are not energy efficient, but the roof is.

4. Which best describes convection?

  D) It is driven by temperature differences within a fluid.

5. A student heats a liquid on a burner. What happens to the portion of liquid that first begins to warm?

  Any answer you choose is correct on Connexus (look at the screenshot)

6. Convection only occurs in ____.

  B) fluids

7. Conduction involves the transfer of electric charge or ____.

  A) thermal energy

8. A scientist designed a foam container to help keep frozen foods from melting. Which best explains how the foam works?

  D) It reduces the amount of thermal energy that is transferred from the inside to the outside of the container.

9. The diagram shows movement of thermal energy. In which areas of the diagram does conduction occur? (look at the screenshot)

  B) X and Z

10. Nuclear reactions in a reactor produce a lot of thermal energy. That energy then flows and warms up water, which boils and produces steam. The stream then turns turbines that generate electricity. Which statement below can be made about the production of electricity in a nuclear reactor?

  B) Heat flows from the reactor to the water.

11. A stovetop burner on medium reaches 200° C. Which other objects will heat from the burner flow to?

     Any answer you choose is correct on Connexus (look at the screenshot)

12. Heat transfer between two substances is affected by specific heat and the

  D) amount of time and area of physical contact between the substances.

13. Which of these results in kinetic energy of an object?

  B) motion

14. Carmen is heating some water and trying to measure the temperature of water using a Celsius thermometer. Which measurement can she expect once the water begins to boil?

  B) 100° C

15. Which shows the formula for converting from degrees to Celsius to degrees Fahrenheit?

   A) °F = (9/5 × °C) + 32

16. Which of these indicates that a liquid has transferred thermal energy to the air?

  D) The liquid decreases in temperature, and its particles lose kinetic energy.

I took the test ALL of these answers are 100% correct on Connexus (they should be the same for everyone tho)

You're welcome and hope this helps!! :)

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A 132 cm wire carries a current of 2.2 A. The wire is formed into a circular coil and placed in a B Field of intensity 1 T. a) F
EastWind [94]

Given Information:

Length of wire = 132 cm = 1.32 m

Magnetic field = B =  1 T

Current = 2.2 A

Required Information:

(a) Torque = τ = ?

(b) Number of turns = N = ?

Answer:

(a) Torque = 0.305 N.m

(b) Number of turns = 1

Explanation:

(a) The current carrying circular loop of wire will experience a torque given by

τ = NIABsin(θ)   eq. 1

Where N is the number of turns, I is the current in circular loop, A is the area of circular loop, B is the magnetic field and θ is angle between B and circular loop.

We know that area of circular loop is given by

A = πr²

where radius can be written as

r = L/2πN

So the area becomes

A = π(L/2πN)²

A = πL²/4π²N²

A = L²/4πN²

Substitute A into eq. 1

τ = NI(L²/4πN²)Bsin(θ)

τ = IL²Bsin(θ)/4πN

The maximum toque occurs when θ is 90°

τ = IL²Bsin(90)/4πN

τ = IL²B/4πN

torque will be maximum for N = 1

τ = (2.2*1.32²*1)/4π*1

τ = 0.305 N.m

(b) The required number of turns for maximum torque is

N = IL²B/4πτ

N = 2.2*1.32²*1)/4π*0.305

N = 1 turn

8 0
4 years ago
1. Determine the image distance in each of the following.
miskamm [114]

It is given that for the convex lens,

Case 1.

u=−40cm

f=+15cm

Using lens formula

v

1

−

u

1

=

f

1

v

1

−

40

1

=

15

1

v

1

=

15

1

−

40

1

v=+24.3cm

The image in formed in this case at a distance of 24.3cm in left of lens.

Case 2.

A point source is placed in between the lens and the mirror at a distance of 40 cm from the lens i.e. the source is placed at the focus of mirror, then the rays after reflection becomes parallel for the lens such that

u=∞

f=15cm

Now, using mirror’s formula

v

1

+

u

1

=

f

1

v

1

+

∞

1

=

15

1

v=+15cm

The image is formed at a distance of 15cm in left of mirror

6 0
3 years ago
Zamir and Talia raced through a maze. Zamir walked 2 m north, 2 m east, 4 m south, 2 m east, 4 m north, 2 m east, 3 m south, 4 m
Alja [10]

Answer : Zamir's displacement and Talia's displacement is equal.

Explanation :

Displacement is explained to be the changing position of an object.

Zamir covers total distance 27 m and Talia covers total distance 19 m but  Zamir's initial and final position and Talia's initial and final position is same.

So, we can say that Zamir's displacement and Talia's displacement is equal.

6 0
3 years ago
Read 2 more answers
A person of mass 70 kg stands at the center of a rotating merry-go-round platform of radius 2.9 m and moment of inertia 900 kg⋅m
Cloud [144]

Explanation:

It is given that,

Mass of person, m = 70 kg

Radius of merry go round, r = 2.9 m

The moment of inertia, I_1=900\ kg.m^2

Initial angular velocity of the platform, \omega=0.95\ rad/s

Part A,

Let \omega_2 is the angular velocity when the person reaches the edge. We need to find it. It can be calculated using the conservation of angular momentum as :

I_1\omega_1=I_2\omega_2

Here, I_2=I_1+mr^2

I_1\omega_1=(I_1+mr^2)\omega_2

900\times 0.95=(900+70\times (2.9)^2)\omega_2

Solving the above equation, we get the value as :

\omega_2=0.574\ rad/s

Part B,

The initial rotational kinetic energy is given by :

k_i=\dfrac{1}{2}I_1\omega_1^2

k_i=\dfrac{1}{2}\times 900\times (0.95)^2

k_i=406.12\ rad/s

The final rotational kinetic energy is given by :

k_f=\dfrac{1}{2}(I_1+mr^2)\omega_1^2

k_f=\dfrac{1}{2}\times (900+70\times (2.9)^2)(0.574)^2

k_f=245.24\ rad/s

Hence, this is the required solution.

5 0
3 years ago
The wasted energy in a charger is:
kirza4 [7]
Thermal is the wasted energy in a charger
4 0
3 years ago
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