Answer:
Day 7 DataUsage notes (since last reading)day & datetimekWh readingkWh usedhours elapsedavg. kW usedb.Usage Extremes: Data CollectionFor this experiment, you’ll measure electrical usage during a time period when you expect to havevery light electrical usage (for instance, while you’re asleep at night or during the day when no oneis at home). Likewise you’ll measure electrical usage during a time period when you expect to have heavier than average electrical usage. This time period might be in the evening, when lights and other appliances are on. Both of these time periods should be at least 4 hours long, to increase the accuracy of your results. Record your results in the tables below for each situation. For each time period, you’ll need to takean initial and a final reading.Type your response here:Low Usage - Initial Readingday & datetimekWh readingLow Usage - Final ReadingEnergy Usage Notesday & datetimekWh readingkWh usedhours elapsedavg. kW usedHigh Usage - Initial Readingday & datetimekWh reading4
Answer:
a)
b) north edge will rise up
Explanation:
torque on the coil is given as
where N is number of loop = 9 loops
i is current = 7.80 A
-B -earth magnetic field = 
A- area of circular coil
A =0.015 m2
PUTITNG ALL VALUE TO GET TORQUE
b) north edge will rise up
Answer:
a. FALSE
b. FALSE
c. TRUTH
d. FALSE
e. FALSE
Explanation:
To determine which statements are truth or false you focus in the following formula, for the electric potential generated by a conducting sphere:
inside the sphere
for r > R (outside the sphere)
R: radius of the sphere
ε0: dielectric permittivity of vacuum
Q: charge of the sphere
As you can notice, inside the sphere the potential is constant. Inside the sphere, the potential is the same. Outside the surface the potential decreases as 1/r, being r the distance to the center of the sphere.
Hence, you can conclude:
a. The potential at the center of the sphere is zero. FALSE
b.The potential is lowest, but not zero, at the center of the sphere. FALSE
c. The potential at the center of the sphere is the same as the potential at the surface. TRUTH
d. The potential at the center is the same as the potential at infinity. FALSE
e. The potential at the surface is higher than the potential at the center. FALSE
Answer:
A. not excludable and not rival in consumption.
Explanation:
Answer:
Explanation:
The whole surface of hollow sphere = 4π r²
= 4 x 3.14 x (10 x 10⁻²)²
= 12.56 x 10⁻² m²
Area of the hole ( both side ) = 2 x π r²
= 2 x 3.14 x (10⁻³)²
= 6.28 x 10⁻⁶ m²
flux coming out of given charge at the centre as per Gauss's theorem
= q / ε₀ where q is charge at the centre and ε₀ is permittivity of the medium .
= 10 x 10⁻⁶ / 8.85 x 10⁻¹²
= 1.13 x 10⁶
This flux will pass through the surface of sphere so flux passing through per unit area
= 1.13 x 10⁶ / 12.56 x 10⁻²
= 8.99 x 10⁶ weber per m²
flux through area of hole
= 8.99 x 10⁶ x 6.28 x 10⁻⁶
= 56.45 weber .
