Answer: D) the significance level of the test
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Explanation:
The significance level of the test, also known as "alpha", is the probability of making a type 1 error. A type 1 error is where you reject the null hypothesis but it was true all along.
The null hypothesis is where we test a certain probability distribution (eg: normal distribution). Specifically we gather a sample of values and compute the test statistic. If the probability of getting that test statistic or more extreme is smaller than alpha, then we reject the null. This probability value is known as the p-value.
If you lower the alpha value, then that will make it more likely you do not reject the null. Consider an example where alpha = 0.10 to start with. If you get a p-value of 0.02, then you would reject the null. The same would apply for alpha = 0.05; however, with alpha = 0.01, the p-value is no longer smaller than alpha. At this point we do not reject the null. Your textbook may use the phrasing "fail to reject the null".
Going in the opposite direction, increasing the alpha value will make it more likely to reject the null. Each time you adjust the alpha value, keep the p-value to some fixed number (between 0 and 1).
Answer:
The solutions of the equation are 0 , π
Step-by-step explanation:
* Lets revise some trigonometric identities
- sin² Ф + cos² Ф = 1
- tan² Ф + 1 = sec² Ф
* Lets solve the equation
∵ tan² x sec² x + 2 sec² x - tan² x = 2
- Replace sec² x by tan² x + 1 in the equation
∴ tan² x (tan² x + 1) + 2(tan² x + 1) - tan² x = 2
∴ tan^4 x + tan² x + 2 tan² x + 2 - tan² x = 2 ⇒ add the like terms
∴ tan^4 x + 2 tan² x + 2 = 2 ⇒ subtract 2 from both sides
∴ tan^4 x + 2 tan² x = 0
- Factorize the binomial by taking tan² x as a common factor
∴ tan² x (tan² x + 2) = 0
∴ tan² x = 0
<em>OR</em>
∴ tan² x + 2 = 0
∵ 0 ≤ x < 2π
∵ tan² x = 0 ⇒ take √ for both sides
∴ tan x = 0
∵ tan 0 = 0 , tan π = 0
∴ x = 0
∴ x = π
<em>OR</em>
∵ tan² x + 2 = 0 ⇒ subtract 2 from both sides
∴ tan² x = -2 ⇒ no square root for negative value
∴ tan² x = -2 is refused
∴ The solutions of the equation are 0 , π
D and B
Explanation:
when you look at that point two lines pass through it and those two lines that pass through it are b and d.
The <u>correct answers</u> are:
16) Mean = 10.25; Median = 10; Range = 17
17) The range.
18) 10
19) 5+5+6+6+7+8+8+8+9+9+10+10+10+10+10+11+12+12+12+13+13+15+15+22 = 246.
Explanation:
16) To find the <u>mean</u>, we first find the sum of the data values in the set:
5+5+6+6+7+8+8+8+9+9+10+10+10+10+10+11+12+12+12+13+13+15+15+22 = 246.
Next we divide this sum by the number of data points, 24:
246/24 = 10.25.
The <u>median</u> is the middle point of a data set. Since there are 24 points, this will be between two values. These two values are 10 and 10; the median is 10.
The <u>range </u>is found by subtracting the highest and lowest values:
22-5 = 17.
17) The <u>mean </u>is changed; the sum of the data values is 246. Taking 22 out of this, the sum is now 223, and we have 23 data points instead of 24; 223/23 = 9.7 for the new mean.
The <u>median </u>does not change; it is still 10.
The <u>range</u> changes; the highest value is now 15, and the lowest is 5: 15-5=10. The range is changed the most.
18) The <u>mean is affected</u> by the outlier and the <u>median is not</u>, so we use the <u>median</u>. This means the answer is 10.
19) The expression for the total number of cars sold is found by adding together all of the points.
