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kobusy [5.1K]
2 years ago
11

What does it mean reflection across ×=3

Mathematics
2 answers:
Advocard [28]2 years ago
4 0
You draw a vertical line on the point (3,0) and a vertical like looks like———>>> | , then whatever shape or point it gives you, you reflect off of that line like if it was a mirror
irina1246 [14]2 years ago
3 0

x = 3 is a vertical line on the coordinate grid which passes through 3 on the x-axis. Imagine  this line to be a mirror  so an object to the left of this line will have an image (its reflection) the same distance  to the right of the line.

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Tomtit [17]

Answer:

I think it's 1.

5 0
2 years ago
Using the answers from z^4=16 determine the solutions of the equation (x+1)^4=16(x-1)^4​
Artemon [7]

i hope i have been useful buddy.

good luck ♥️♥️♥️♥️♥️.

4 0
3 years ago
A recipe needs 3/4 cup of water for every 2 cups of flour. If you to use 6 cups of flour, how much water will you need?
Diano4ka-milaya [45]

Answer:

2 1/4 or 2.25

Step-by-step explanation:

2*3= 6

3/4*3= 2 1/4

4 0
2 years ago
Help with this number 3)is 2×=-8
IRISSAK [1]
2x= -8
2x/2=-8/2
X= -4
6 0
2 years ago
Researchers fed mice a specific amount of Dieldrin, a poisonous pesticide, and studied their nervous systems to find out why Die
Elodia [21]

Answer:

Step-by-step explanation:

Part A

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

6 0
3 years ago
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