Answer:
A circle is centered at the point (-3,2) and passes through the point (1,5). The radius of the circle is (5 ) units. the point (-7, -1) and point (-7, 5) lies in this circle.
Step-by-step explanation:
equation of circle is
(X-center_X)^2 + (y-center_Y)^2 = r^2
==> (x+3)^2 + (y-2)^2 = r^2
Now it passes 1,5 so
4^2+3^2 = 5^2
==> r = 5
when x = -7
y = -1 or 5
Answer:
Here we just want to find the Taylor series for f(x) = ln(x), centered at the value of a (which we do not know).
Remember that the general Taylor expansion is:
for our function we have:
f'(x) = 1/x
f''(x) = -1/x^2
f'''(x) = (1/2)*(1/x^3)
this is enough, now just let's write the series:
This is the Taylor series to 3rd degree, you just need to change the value of a for the required value.
Answer:
b
Step-by-step explanation:
Answer:
For this case we have the following fraction:
To find the common denominator, what we must do is rewrite the fraction.
For this, we subtract fractions in the numerator and the sum of fractions in the denominator.
We have then:
We observe that the common denominator is given by the product:
Answer:
the common denominator is:
D)ab
Step-by-step explanation:
