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Natasha_Volkova [10]
3 years ago
8

Help plz! I will give you brainliest if ur right:)

Mathematics
2 answers:
Reptile [31]3 years ago
8 0

Answer: a

Step-by-step explanation:

KengaRu [80]3 years ago
7 0
I just solved this and the answer is A for your question I hope this helps! :)
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Diagram for 19x50<br><br> Right answers only
Schach [20]

Answer:

950?

Step-by-step explanation:

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Is 9 7/8 irrational or rational?
Karo-lina-s [1.5K]

Answer:irrational

Step-by-step explanation: it is not a whole number

5 0
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2. Mrs. Frederick is paid semimonthly.
Julli [10]

The annual salary of Mrs. Fredrick is $ 39397.2

<u>Solution:</u>

Given, Mrs. Frederick is paid semimonthly.  

Her semi-monthly salary is $1.641.55.  

Now, let us find her monthly salary first.

<em>monthly salary = 2 x semi – monthly salary </em>

So, monthly salary = 2 x 1,641.55 = $ 3283.1

Since there 12 months in a year, we obtain the annual salary as follows:

Now, the<em> annual salary = 12 x monthly salary </em>

Annual salary = 12 x 3283.1  = $ 39397.2

Hence, the annual salary of Mrs. Fredrick is $ 39397.2

5 0
3 years ago
What is 5292cm rounded to the nearest thousandth
krek1111 [17]

the answer to that question is 6000

4 0
3 years ago
Find+the+positive+value+for+α+if+the+radius+of+the+circle+3x^2+3y-6αx+12y-3α=0+is+4
Alik [6]

Answer:

\alpha=3

Step-by-step explanation:

<u>Equation of a Circle</u>

A circle of radius r and centered on the point (h,k) can be expressed by the equation

(x-h)^2+(y-k)^2=r^2

We are given the equation of a circle as

3x^2+3y^2-6\alpha x+12y-3\alpha=0

Note we have corrected it by adding the square to the y. Simplify by 3

x^2+y^2-2\alpha x+4y-\alpha=0

Complete squares and rearrange:

x^2-2\alpha x+y^2+4y=\alpha

x^2-2\alpha x+\alpha^2+y^2+4y+4=\alpha+\alpha^2+4

(x-\alpha)^2+(y+2)^2=r^2

We can see that, if r=4, then

\alpha+\alpha^2+4=16

Or, equivalently

\alpha^2+\alpha-12=0

There are two solutions for \alpha:

\alpha=-4,\ \alpha=3

Keeping the positive solution, as required:

\boxed{\alpha=3}

8 0
3 years ago
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