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fomenos
2 years ago
8

Consider the reaction. When does the given chemical system reach dynamic equilibrium? when the forward and reverse reactions sto

p when the rate of the forward reaction is higher than the rate of the reverse reaction when the concentration of the reactants is higher than the concentration of the products when the rates of the forward and reverse reactions are equal
Chemistry
1 answer:
coldgirl [10]2 years ago
3 0

Answer: when the rates of the forward and reverse reactions are equal

Explanation:

The reactions which do not go on completion and in which the reactant forms product and the products goes back to the reactants simultaneously are known as equilibrium reactions.

Equilibrium state is the state when reactants and products are present but the concentrations does not change with time.

The equilibrium is dynamic in nature and the reactions are continuous in nature. Rate of forward reaction is equal to the rate of backward reaction.

A chemical equilibrium is dynamic in nature as forward and backward reactions continue for indefinite time and never stops.

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Please help me solve this!
yulyashka [42]

Answer : The image is attached below.

Explanation :

For O_3:

Molar mass, M = 48 g/mol

Mass, m = 24 g

Moles, n = \frac{m}{M}=\frac{24g}{48g/mol}=0.5mol

Number of particles, N = n\times 6.022\times 10^{23}=0.5\times 6.022\times 10^{23}=3.0\times 10^{23}

For NH_3:

Molar mass, M = 17 g/mol

Mass, m = 170 g

Moles, n = \frac{m}{M}=\frac{170g}{17g/mol}=10mol

Number of particles, N = n\times 6.022\times 10^{23}=10\times 6.022\times 10^{23}=6.0\times 10^{24}

For F_2:

Molar mass, M = 38 g/mol

Mass, m = 38 g

Moles, n = \frac{m}{M}=\frac{38g}{38g/mol}=1mol

Number of particles, N = n\times 6.022\times 10^{23}=1\times 6.022\times 10^{23}=6.0\times 10^{23}

For CO_2:

Molar mass, M = 44 g/mol

Moles, n = 0.10 mol

Mass, m = n\times M=0.10mol\times 44g/mol=4.4g

Number of particles, N = n\times 6.022\times 10^{23}=0.10\times 6.022\times 10^{23}=6.0\times 10^{22}

For NO_2:

Molar mass, M = 46 g/mol

Moles, n = 0.20 mol

Mass, m = n\times M=0.20mol\times 46g/mol=9.2g

Number of particles, N = n\times 6.022\times 10^{23}=0.20\times 6.022\times 10^{23}=1.2\times 10^{23}

For Ne:

Molar mass, M = 20 g/mol

Number of particles = 1.5\times 10^{23}

Moles, n = \frac{N}{6.022\times 10^{23}}=\frac{1.5\times 10^{23}}{6.022\times 10^{23}}=0.25mol

Mass, m = n\times M=0.25mol\times 20g/mol=5g

For N_2O:

Molar mass, M = 44 g/mol

Number of particles = 1.2\times 10^{24}

Moles, n = \frac{N}{6.022\times 10^{23}}=\frac{1.2\times 10^{24}}{6.022\times 10^{23}}=1.9mol

Mass, m = n\times M=1.9mol\times 44g/mol=83.6g

For unknown substance:

Number of particles = 3.0\times 10^{23}

Mass, m = 8.5 g

Moles, n = \frac{N}{6.022\times 10^{23}}=\frac{3.0\times 10^{23}}{6.022\times 10^{23}}=0.50mol

Molar mass, M = \frac{m}{n}=\frac{8.5g}{0.50mol}=17g/mol

The substance is NH_3.

3 0
2 years ago
State the equation which explain how to find the energy of a photon.
Norma-Jean [14]

Answer: To find the energy of a photon you want to use this equation: E=hf

Explanation: E is the energy of the photon in Joules; h is Planck's constant, which is always 6.63*10^-34 Joule seconds; and f is the frequency of the light in hertz.

6 0
3 years ago
3. How did ethanol use affect the shortage of corn available to consumers during and
torisob [31]

Answer:

Yes.

Explanation:

Yes, commodities in one sector should be used  in another sector because scientist invented methods in which one commodity is used in several sectors for the production of new products. Corn was used for the production of ethanol which causes the shortage of corn that was available to consumers during and  after the drought condition of 2012. Due to drought, the production of corn decreases and shortage of it occurs.

3 0
3 years ago
What is agriculture​
DedPeter [7]

Answer:

the science or practice of farming, including cultivation of the soil for the growing of crops and the rearing of animals to provide food, wool, and other products.

4 0
3 years ago
Which method would be best to separate a mixture of oil and water? separation by density separation by particle size filtration
soldi70 [24.7K]
I think filtration. I hope its correct :) 
4 0
2 years ago
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