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Airida [17]
4 years ago
13

Solve for y. Enter your answer in the box. An equilateral triangle A B C. Side B C is the base. Sides A B, B C, and A C are equa

l. Sides A B, B C, and A C are labeled with single tick marks. Angle A is labeled as left parenthesis 5 y plus 10 right parenthesis degrees, and angle C is labeled as left parenthesis 6 x plus 6 right parenthesis degrees.
Mathematics
1 answer:
Strike441 [17]4 years ago
6 0

Answer:

y = 10

Step-by-step explanation:

By definition, the internal angles of an equilateral triangle are all 60. So:

A = 5y + 10 = 60

5y + 10 = 60

5y + 10 - 10 = 60 - 10

5y = 50

5y/5 = 50/5

y = 10

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thats it!
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A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measurin
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Answer:

The standard deviation of weight for this species of cockroaches is 4.62.

Step-by-step explanation:

Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

To find : What is the approximate standard deviation of weight for this species of cockroaches?

Solution :

We have given,

Mean \mu=50

The sample mean x=55

A lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

i.e. P(X>55)=14%=0.14

The total probability needs to sum up to 1,

P(X\leq 55)=1-P(X>55)

P(X\leq 55)=1-0.14

P(X\leq 55)=0.86

The z-score value of 0.86 using z-score table is z=1.08.

Applying z-score formula,

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Where, \sigma is standard deviation

Substitute the values,

z=\frac{x-\mu}{\sigma}

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\sigma=\frac{5}{1.08}

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The standard deviation of weight for this species of cockroaches is 4.62.

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