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wariber [46]
3 years ago
14

Line c passes through points (2, 1) and (6, 6). Line d is parallel to Line c. What is the slope to line d?

Mathematics
1 answer:
Lilit [14]3 years ago
8 0

Answer:

\frac{5}{4}

Step-by-step explanation:

We need to find the formula of line c

\left \{ {{a*2+b=1} \atop {6*a+b=6} \right.

Subtract these two

-4*a=-5

a=\frac{5}{4}

And lies c and d will be paraller if a_{c}= a_{d}

so a_{d}=\frac{5}{4}

And that's the slope to line d

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The expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8.</u>

The power-reducing formula, for cosine, is,

cos² θ = (1/2)[1 + cos 2θ].

In the question, we are asked to use the formulas for lowering powers to rewrite the expression in terms of the first power of cosine cos⁴ θ.

We can do it as follows:

cos⁴ θ

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= {(1/2)[1 + cos 2θ]}²

= (1/4)[1 + cos 2θ]²

= (1/4)(1 + 2cos 2θ + cos² 2θ] {Using (a + b)² = a² + 2ab + b²}

= 1/4 + (1/2)cos 2θ + (1/4)(cos ² 2θ)

= 1/4 + (1/2)cos 2θ + (1/4)(1/2)[1 + cos 4θ]

= 1/4 + cos 2θ/4 + 1/8 + cos 4θ/8

= 3/8 + cos 2θ/4 + cos 4θ/8

= [ 3 + 2cos 2θ + cos 4θ]/8.

Thus, the expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8</u>.

Learn more about reducing trigonometric powers at

brainly.com/question/15202536

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