Answer:
for Lena
C = 3x C + 5x
for Patrick
C = 9x C = 10x
for total C = 12x + 15x
Step-by-step explanation:
Part A:
Given that <span>Starlight tree farms sells Douglas Firs and Noble First.
Let </span>n be the number of Noble Fir trees sold, then<span> if they sold 139 more Douglas First than Noble Firs, this means that the number of Douglas First trees sold is n + 139.
Given that the total number of trees sold was 377, then we have, n + n + 139 = 377, which means that 2n + 139 = 377
Therefore, the equation that could be used to solve for n, the number of Noble Fir trees sold is 2n + 139 = 377.
Part B:
</span><span>Given that you are driving 55 miles per hour and you must drive a total of 440 miles. If you already driven 275 miles, then, the equation representing the number of hours, h, it will take to reach your destination is given by 55h + 275 = 440.
Subtracting 275 from both sides of the equation gives:
</span>

<span>
Dividing both sides by 55 gives:
</span>

<span>
Therefore, the time it will take you to reach your destination is 3 hours.</span>
Answer:
The amount that we should deposit in each bank is around $942.
Step-by-step explanation:
Case 1:
A=$1000
n = 12
t = 2
r = 3% or 0.03
p = ?
The compound interest formula is :

Substituting values in the formula;

=> 
=> 

p = $941.84
Case 2:
A=$1000
n = 365
t = 2
r = 3% or 0.03
p = ?

=> 
=>

p = $941.76
The amount that we should deposit in each bank is around $942.
Median and IQR are the most appropriate measures of center and spread for this data set.
<h3>Why are
Median and IQR the most appropriate?</h3>
Among the 3 central tendencies that includes the mean, median and mode; the median is the better measure because of the followings:
- Mean is affected by extreme values
- Mean is not correct if more outliers are present
- Mean may not represent the nature of the data whether skewed right or left.
Also, the median as the middle entry is not affected by extreme items or outliers, so the median is better than mean,
Furthermore, for the measure of spread, the IQR is better since extreme items will show higher std deviation and also some outliers mislead.
Therefore, Option B is correct.
Read more about measures of center
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