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scZoUnD [109]
4 years ago
12

Point Q(-1,5) is reflected across the line x=-1. What are the coordinates of its image?

Mathematics
1 answer:
natta225 [31]4 years ago
8 0

Answer:

(- 1, 5 )

Step-by-step explanation:

Since the x- coordinate of Q, x = - 1 lies on the line of reflection.

The point Q will remain unchanged, that is

coordinates of image are (- 1, 5 )

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3 years ago
Find the endpoint:
scZoUnD [109]

Answer:

The coordinates of Point D are: (-5,-8)

Step-by-step explanation:

The formula for mid-point is given by:

M = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})

For the point (x1,y1) and (x2,y2)

Given that

M = (-3, -6)

C = (-1, -4) => (x1,y1)

Putting the values of given points in the formula for mid-point

(-3,-6) = (\frac{-1+x_2}{2} , \frac{-4+y_2}{2})

Putting respective coordinates equal

-3 = \frac{-1+x_2}{2}\\-6 =-1+x_2\\x_2=-6+1\\x_2 = -5\\AND\\-6 = \frac{-4+y_2}{2}\\-12 = -4+y_2\\y_2 = -12+4\\y_2 = -8

Hence,

The coordinates of Point D are: (-5,-8)

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3 years ago
The base of a triangle is 3 cm longer than its altitude. The area of the triangle is 35cm^2. Find the altitude. (Hint: use the a
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Which is not a correct way to rewrite this expression using the distributive
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Given:

The expression is

(2x^2+4x-7)(x-2)

To find:

The expression which is not a correct way to rewrite the given expression.

Solution:

We have,

(2x^2+4x-7)(x-2)

Using distributive property, we get

=(2x^2)(x-2)+(4x)(x-2)+(-7)(x-2)

=(2x^2)(x)+(2x^2)(-2)+(4x)(x)+(4x)(-2)+(-7)(x)+(-7)(-2)

Using distributive property the given expression can rewritten as:

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