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Likurg_2 [28]
3 years ago
11

I dont understand this problem. please help and explain answer 10x=y/5

Mathematics
1 answer:
Shtirlitz [24]3 years ago
3 0
Take 5 to the left:
(10×5)x = y
50x = y
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#1) Mrs. Ebanks planted two trees on a
uranmaximum [27]

Answer:

D = 12.94 m

Step-by-step explanation:

Coordinates of first tree = A(0,8)

Coordinates of second tree = A(12,4)

We need to find the distance between the two trees. We can find it using distance formula for coordinates as follows :

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have, x₁ = 0, x₂ = 12, y₁ = 8, y₂ = 4

Now using distance formula,

D=\sqrt{(12-0)^2+(4-8)^2}\\\\=\sqrt{144+16} \\\\=12.64\ m

So, the distance between the two trees is 12.64 m.

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3 years ago
Water flows into a conical container (radius:12cm, height:18cm) as shown below at the rate of 2cm^3 s^-1
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Answer:

where is the as shown below?

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3 years ago
Can someone help me with this thanks ​
Ugo [173]

The length of the brace required is 4.3m

What is sine rule?

In a ΔABC a, b and c are the sides and A, B and C are angles then,

\frac{a}{SinA}=\frac{b}{sinB}=\frac{c}{sinC}

We can find the length, l as shown below:

Let AB=3m, BC=2m and AC=l

Let ∠A=25°

So, in ΔABC

\frac{BC}{sinA}=\frac{AB}{sinC}=\frac{AC}{SinB}

\frac{BC}{sinA}=\frac{AB}{sinC}

\frac{2}{sin25}=\frac{3}{sinC}

\angle{C}=sin^{-1}(\frac{3\times sin25}{2} )

∠C=39.34°

∠A+∠B+∠C=180°

∠B=180°-25°-39.34°

∠B=115.66°

\frac{BC}{sinA}=\frac{AC}{SinB}

\frac{2}{sin25}=\frac{l}{sin(115.66)}

l=\frac{2\times sin(115.66)}{sin25}

l=4.2659

Rounding to nearest tenth of meter.

l=4.3m

Hence, the length of the brace required is 4.3m

Learn more about Sine Rule here:

brainly.com/question/25852087

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2 years ago
A 45 gm tube of 1% clotrimazole cream is combined with 15gm of base. What is the new % strength ?
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0.75% is the answer the our question
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4 years ago
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When the shape of a bst approaches that of a perfectly balanced binary tree, what is the worst case performance characteristic o
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The shape of a bst approaches that of a perfectly balanced binary tree, (log2n) is the time complexity for a balanced binary search tree in case of insertions and search.

In computing, binary bushes are mainly used for looking and sorting as they offer a way to save statistics hierarchically. a few common operations that may be conducted on binary trees encompass insertion, deletion, and traversal.

A binary tree has a special situation that each node could have a most of two youngsters. A binary tree has the benefits of each an ordered array and a linked listing as search is as brief as in a taken care of array and insertion or deletion operation are as fast as in related listing.

In pc science, a binary tree is a tree information shape in which every node has at maximum two youngsters, that are known as the left baby and the proper toddler.

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2 years ago
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