Answer:

Explanation:
Hello there!
In this case, given the solubilization of cadmium (II) hydroxide:

The solubility product can be set up as follows:
![Ksp=[Cd^{2+}][OH^-]^2](https://tex.z-dn.net/?f=Ksp%3D%5BCd%5E%7B2%2B%7D%5D%5BOH%5E-%5D%5E2)
Now, since we know the concentration of cadmium (II) ions at equilibrium and the mole ratio of these ions to the hydroxide ions is 1:2, we infer that the concentration of the latter at equilibrium is 3.5x10⁻⁵ M. In such a way, the resulting Ksp turns out to be:

Regards!
Answer:
Sulfur (Option-C) <span>exhibits chemical behavior similar to that of oxygen.
Explanation:
Sulfur has same chemical properties as that of Oxygen because both of them belongs to same group in the periodic table. Also, the similarity of chemical behaviour among the group members is due to same number of electrons in their valence shells.
For examole, the electronic configuration of Oxygen is,
1s</span>², 2s², 2p⁴
There are six valence electrons in the valence shell (i.e. 2) of Oxygen.
Now for Sulfur,
1s², 2s², 2p⁶, 3s², 3p⁴
There are six valence electrons in the valence shell (i.e. 3) of Sulfur.
Therefore, both elements tends to gain 2 electrons in a reaction and form O⁻² and S⁻² respectively.
Answer:
A. Kilo , K, multiplication by 1000
B. Centi, c
C. Deci, d
D. Mili, m
E. Mega, M
F. Micro, u
Was .08 off its 4.08 like that guy explained