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3 years ago

What is the difference between ionic and covalent compounds?

Chemistry

1 answer:

k0ka [10]3 years ago

8 0

<h3>Answer;</h3>

D. All the above

Covalent compounds are always poor conductors of electricity while ionic compounds conduct electricity well when melted or dissolved.
Covalent compounds can be solid, liquid or gas, but ionic compounds are solids.
In covalent compounds the elements present are usually close together on the periodic table whereas in ionic compounds they are usually well separated.

<h3>Explanation;</h3>

Ionic compounds are compounds that are formed from strong electrostatic interactions between ions. Ionic bonding occurs between a nonmetal, which acts as an electron acceptor, and a metal, which acts as an electron donor. The atoms involved in ionic bonding lose or gain electrons and form positively or negatively charged ions.
Ionic compound are good conductors of electricity both in molten and aqueous form,. while covalent compound are poor conductors of electricity.
Covalent compounds on the other hand are compounds that have bonds where electrons are shared between atoms. These types bonds mostly occur between nonmetals or between two atoms of the same element.

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Which aqueous solution has the highest boiling point at standard pressure?(1) 1.0 M KC1(aq) (3) 2.0 M KCl(aq)(2) 1.0 M CaC12(aq)

miss Akunina [59]

Answer:

(4) 2.0 M CaCl₂(aq).

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ΔTb = i.Kb.m,

where, ΔTb is the elevation in boiling point.

i is the van 't Hoff factor.

van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

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m is the molality of the solution.

(1) 1.0 M KCl(aq):

i for KCl = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

suppose molarity = molality, m = 1.0 m,

∴ ΔTb for (1.0 M KCl) = i.Kb.m = (2)(Kb)(1.0 m) = 2(Kb).

(2) 2.0 M KCl(aq):

i for KCl = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

suppose molarity = molality, m = 2.0 m,

∴ ΔTb for (1.0 M KCl) = i.Kb.m = (2)(Kb)(2.0 m) = 4(Kb).

(3) 1.0 M CaCl₂(aq):

i for CaCl₂ = no. of particles produced when the substance is dissolved/no. of original particle = 3/1 = 3.

suppose molarity = molality, m = 1.0 m,

∴ ΔTb for (1.0 M KCl) = i.Kb.m = (3)(Kb)(1.0 m) = 3(Kb).

(4) 2.0 M CaCl₂(aq):

i for CaCl₂ = no. of particles produced when the substance is dissolved/no. of original particle = 3/1 = 3.

suppose molarity = molality, m = 2.0 m,

∴ ΔTb for (1.0 M KCl) = i.Kb.m = (3)(Kb)(2.0 m) = 6(Kb).

So, the aqueous solution has the highest boiling point at standard pressure is: (4) 2.0 M CaCl₂(aq).

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3 years ago