It might be 9 if it's not 6 ...but I can't see how it wouldn't be 6?
2 ( k-5) 13 you don't need two k-5 you can simplify it so you just know to do it twice
Left side I think is A is 12 sandcastles and B is 20 sandcastles.
Step-by-step explanation:
1.77 would be closer to 2
Answer:
Kite is a quadrilateral in which two disjoint pairs of consecutive sides are congruent
Given: In kite PQRS
where PR and SQ are the diagonals of Kite respectively as shown in the figure given below.
Given: TQ = 3 cm and TP = 4 cm
Let PR is the main diagonal and SQ is the cross diagonal of kite PQRS as shown in figure, also let T is the intersection point of PQRS.
By Property of Kite, diagonal SQ bisects PR at perpendicular angle i.e, 90 degree.
i,e
Then, in right angle ΔQTP
[Using Pythagoras theorem]
Substitute the given values of TQ and TP we have;

Also, PQ = SP [by definition of kite]
therefore, the side SP = 5 cm.