A lighthouse keeper has a 10 degrees angle of depression between the horizontal light beam and the line of sight from the ship.
1 answer:
107.75m
This is a trigonometric ratio problem. the angle of depression (10) is opposite the height (19m) and the distance is adjacent to the distance (x). opposite ad adjacent sides to the angle is a tangent problem.
plus in values, we know.
switch tan(10) and x using the products property.
plug in to calulator to get answer
x=107.75
This is a trigonometric ratio problem. the angle of depression (10) is opposite the height (19m) and the distance is adjacent to the distance (x). opposite ad adjacent sides to the angle is a tangent problem.
plus in values, we know.
switch tan(10) and x using the products property.
plug in to calulator to get answer
x=107.75
You might be interested in
So... let's say the amounts invested were "a" at 6% and "b" at 7.5%.
ok.. hmm what's 6% of a? well, (6/100) * a or 0.06a.
what's 7.5% of b? well, (7.5/100) * b or 0.075b.
now... we know, whatever "a" and "b" are, they total the investment of 5000 bucks, thus a + b = 5000
and the interest yielded was 337.50, thus 0.06a + 0.075b = 337.50
thus
solve for "a", to see how much was invested at 6%.
what about "b"? well, b = 5000 - a.
ok.. hmm what's 6% of a? well, (6/100) * a or 0.06a.
what's 7.5% of b? well, (7.5/100) * b or 0.075b.
now... we know, whatever "a" and "b" are, they total the investment of 5000 bucks, thus a + b = 5000
and the interest yielded was 337.50, thus 0.06a + 0.075b = 337.50
thus
solve for "a", to see how much was invested at 6%.
what about "b"? well, b = 5000 - a.