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Anestetic [448]
3 years ago
13

Unlike other states of matter, what expand to fill their containers

Physics
2 answers:
padilas [110]3 years ago
8 0

Answer:

gas

Explanation:

BigorU [14]3 years ago
4 0

Answer:

Person above me is big brain!

Explanation:

They are correct!

Give them some love and mark them as brainliest!

You might be interested in
Which of the following two elements will likely form an ionic bond?
julsineya [31]
The answer is B.) I took the test. 
5 0
3 years ago
Read 2 more answers
As an electron approaches a proton, the electron's force of attraction...
Tems11 [23]

Answer: B. Increases

Explanation:

An electron is a negatively charged particle, while a proton is positively charged.

Opposites attract so as it approaches the proton the force of attraction will increase.

7 0
3 years ago
The first-order rearrangement of CH3NC is measured to have a rate constant of 3.61 × 10–15 s–1 at 298 K and a rate constant of 8
netineya [11]

Answer:

The activation energy for this reaction, Ea = 159.98 kJ/mol

Explanation:

Using the Arrhenius equation as:

ln\frac {K_2}{K_1}=-\frac {E_a}{R}\times (\frac {1}{T_2}-\frac {1}{T_1})

Where, Ea is the activation energy.

R is the gas constant having value 8.314 J/K.mol

K₂ and K₁ are the rate constants

T₂ and T₁ are the temperature values in kelvin.

Given:

K₂ = 8.66×10⁻⁷ s⁻¹ , T₂ = 425 K

K₁ = 3.61×10⁻¹⁵ s⁻¹ , T₁ = 298 K

Applying in the equation as:

ln\frac {8.66\times 10^{-7}}{3.61\times 10^{-15}}=-\frac {E_a}{8.314}\times (\frac {1}{425}-\frac {1}{298})

Solving for Ea as:

Ea = 159982.23 J /mol

1 J/mol = 10⁻³ kJ/mol

Ea = 159.98 kJ/mol

7 0
3 years ago
How to find the period of a wave
____ [38]
The method to choose depends on what information you have, and
on what you can measure.  Here are a few possible methods:

-- Measure the period. Start your clock when one peak
of the wave passes you.  Stop the clock when the next
peak passes you.  The time between the two peaks is
the wave's period.

-- Divide the wave's wavelength by its speed.  That quotient
is the wave's period.

-- Use an electronic frequency meter to measure the wave's
frequency.  Then take its reciprocal (divide ' 1 ' by it).  The
result is the wave's period.
5 0
4 years ago
A photoelectric experiment is performed where green light with a wavelength of 546.1 nm is shined on a metal plate, creating a p
PtichkaEL [24]

Answer:

\phi=1.55 [eV]

Explanation:

We can use the work function equation for a photoelectric experiment:

\phi=\frac{hc}{\lambda}-K_{max}

  • h is the plank constant
  • c is the speed of light
  • λ is the wave length
  • K is the kinetic energy (or K=eΔV)

So we will have:

\phi=\frac{hc}{\lambda}-e\Delta V

\phi=\frac{6.63*10^{-34}*3*10^{8}}{546.1*10^{-9}}-0.728eV    

\phi=3.64*10^{-19}[J]-0.728 [eV]

\phi=(3.64*10^{-19}[J]*\frac{1eV}{1.6*10^{-19}[J]})-0.728 [eV]

\phi=2.28 [eV] - 0.728 [eV]

\phi=1.55 [eV]

I hope it helps you!

8 0
4 years ago
Read 2 more answers
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