1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KATRIN_1 [288]
3 years ago
15

What is the acceleration of a 25 kg mass pushed by a 10n force

Physics
2 answers:
Kamila [148]3 years ago
5 0

f divided by m = a


a = 0.4

Sidana [21]3 years ago
5 0

Answer:

The answer is acceleration is equal to 0.4m/s^2

Step by Step Explanation:

1) Acceleration is a vector derived magnitude that indicates the variation of speed per unit of time.

2) Taking into account Newton's Second Law, which determines a proportional relationship between force and variation in the amount of movement or linear momentum of a body. That is, the force is directly proportional to the mass and acceleration of a body.

3) This law is expressed by the formula F = m.a where (F) represents Force (m) represents mass and (a) represents acceleration.

4) Knowing this we can issolate (a) from the formula and we would have:

a = \frac{F}{m}

5) Having this we can now replaces the values given in the problem.

a = \frac{10N}{25Kg} \\a = 0.4

You might be interested in
Which of the following can be the first step to take in organizing data
Natalka [10]

the first step would be gathering information , and making sure its correct

5 0
3 years ago
When you are riding in a car then the driver suddenly steps on the gas pedal, why do you feel a jolt and push back?
inessss [21]

Answer:

due to acceleration lol

4 0
3 years ago
Read 2 more answers
If you push a 4-kg mass...
Lena [83]

Answer:

B

Explanation:

F = ma , a = F/m

a1 = F/10 and a2 = F/4

Since Force is constant, a2 will we greater than a1

4 0
3 years ago
A car travels 5 km due east, then 10 km due north, and then 5
Rufina [12.5K]

Answer:

idk what the answer plz help!!!

Explanation:

8 0
3 years ago
A large bottle contains 150 L of water, and is open to the atmosphere. If the bottle has a flat bottom with an area of 2 ft, cal
Yuri [45]

Answer:

Total pressure exerted at bottom =  119785.71 N/m^2

Explanation:

given data:

volume of water in bottle = 150 L = 0.35 m^3

Area of bottle = 2 ft^2

density of water = 1000 kg/m

Absolute pressure on bottom of bottle will be sum of atmospheric pressure and pressure due to water

Pressure due to water P = F/A

F, force exerted by water = mg

m, mass of water = density * volume

                             =  1000*0.350 = 350 kg

F  = 350*9.8 = 3430 N

A = 2 ft^2 = 0.1858 m^2  

so, pressure P = 3430/ 0.1858 = 18460.71 N/m^2

Atmospheric pressure

At sea level atmospheric pressure is 101325 Pa

Total pressure exerted at bottom  = 18460.71 + 101325 = 119785.71 N/m^2

Total pressure exerted at bottom =  119785.71 N/m^2

6 0
3 years ago
Other questions:
  • This is a device that will convert mechanical, into electrical energy.
    13·2 answers
  • The atmospheric pressure in denver, co is 633 mmhg. what is this pressure in atm?
    7·1 answer
  • When you throw a pebble straight up with initial speed V, it reaches a maximum height H with no air resistance. At what speed sh
    7·1 answer
  • Assume that the polymer material has a constant refractive index of 1.5. For light of 600nm wavelength at normal incidence, what
    15·1 answer
  • If you are about to be hit from behind, your best course of action is to brake gently and stop the car.
    7·1 answer
  • Pls help me quick im doing a quiz
    9·2 answers
  • What is newton's second law of motion?
    5·1 answer
  • at a temperature of 10 c,700 ml of hydrogen is collected. if this gas is put into a 1000 ml container what will its new temperat
    12·2 answers
  • How much work is done when a porcelain vase with mass of 2.5 kg is lifted up 3 m to a shelf? (HINT- Weight can be used as Force
    7·1 answer
  • SORRY LAST ONE FOR TODAY, IM GOING TO PASS IF I GET THIS ANSWERED
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!