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4 years ago

What is the acceleration of a 25 kg mass pushed by a 10n force

Physics

2 answers:

Kamila [148]4 years ago

5 0

f divided by m = a

a = 0.4

Sidana [21]4 years ago

5 0

Answer:

The answer is acceleration is equal to 0.4m/s^2

Step by Step Explanation:

1) Acceleration is a vector derived magnitude that indicates the variation of speed per unit of time.

2) Taking into account Newton's Second Law, which determines a proportional relationship between force and variation in the amount of movement or linear momentum of a body. That is, the force is directly proportional to the mass and acceleration of a body.

3) This law is expressed by the formula F = m.a where (F) represents Force (m) represents mass and (a) represents acceleration.

4) Knowing this we can issolate (a) from the formula and we would have:

$a = \frac{F}{m}$

5) Having this we can now replaces the values given in the problem.

$a = \frac{10N}{25Kg} \\a = 0.4$

You might be interested in

Distinguish between a meteor, a meteoroid, and a meteorite.

leonid [27]

Answer:

The distinction can be understood by their individual definitions given below.

Explanation:

A meteoroid is a small rocky/metallic body that can be found in outer space (space beyond the Earth's atmosphere). Their sizes are much smaller than asteroids (often called planetoids) and even more smaller than that of any planets or their moons. They generally originate from comets, asteroids (fragments of them) and even from planets or moons when there occurs heavy collisions.

A meteor is basically what we know to be "shooting stars". When a meteoroid, asteroid, etc. passes through the Earth's atmosphere, they heat up and begin to glow because of the frictional force experienced due to gas molecules in the atmosphere. But the important thing is that they do not reach the surface of the Earth as they completely burn out long before coming close. If some object does manage to reach the Earth's surface, we then call it a meteorite.

(These definitions are not restricted to the Earth but applies to all panets and moons.)

(Also check the gif provided here: https://en.wikipedia.org/wiki/Meteoroid)

8 0

3 years ago

A bowler throws a bowling ball of radius R = 11.0 cm down the lane with initial speed = 8.50 m/s. The ball is thrown in such a w

Ad libitum [116K]

Answer:

a) 1.18 seconds

b) 8.6 m

c) 5.19 revolutions

d) 6.07 m/s

Explanation:

Step 1: Data given

radius of the ball = 11.0 cm

Initial speed of the ball = 8.50 m/s

The coefficient of kinetic friction between the ball and the lane is 0.210.

(a) For what length of time does the ball skid?

The velocity at time t can be written as v(t) = v0 + at

⇒ with v(t) = the velocity at time t

⇒ with v0 : the initial velocity = 8.50 m/s

⇒ with a = the acceleration (in m/s²)

⇒The acceleration (negative) due to friction: a = -µg

⇒ with µ = 0.210

⇒ with g = 9.81 m/s²

v(t) =8.5m/s - 0.21*9.81m/s² * t = 8.5 - 2.06t

Torque τ = Iα = (2m(0.11m)²/5)α = 0.00484m*α

τ = F * r = µm*g*R = 0.21 * M * 9.81m/s² * 0.11m = 0.227m

so α = 0.227m / 0.00484m = 46.9 rad/s²

angular velocity ω(t) = ωo + αt = 0 + 46.9 rad/s² * t

The ball stops sliding when v(t) = ω(t) * r

8.5 - 2.06t = 46.9*0.11*t = 5.159t

7.219t = 8.5

t = 1.18 seconds

b) How far down the lane does it skid?

s = Vo*t + ½at² = 8.5m/s * 1.18s - ½* 2.06 m/s² * (1.18s)² = 8.6 m

c) How many revolutions does it make before it starts to roll?

The angular acceleration of the ball is:

α = τ/I

⇒ with τ = the torque experienced by the ball due the frictional force

⇒ τ = fk*R

α = fk*R /I

⇒ I = 2/5 m*R²

⇒ fk = µk*m*g

α = (µk*m*g*R)/(2/5mR²)

α = 5µk*g /2R

The angular displacement of the ball is:

∅ = 1/2αt²

⇒ The ball does not have an initial angular velocity

∅ =1/2*(5µk*g/2)*t²

∅ = 5µkgt²/4R

∅ = (5*0.21*9.81*1.18²)/(4*11.0 *10^-2)

∅ = 32.6 rad

Number of revolutions = 32.6 rad /2π

Number of revolutions = 5.19

(d) How fast is it moving when it starts to roll?

v = Vo + at = 8.5m/s - 2.06m/s² * 1.18s = 6.07 m/s

7 0

3 years ago

How much energy can be stored in a spring with k = 470 n/m if the maximum possible stretch is 17.0 cm ?

MrRissso [65]

The strain energy stored in a linear spring is
SE = (1/2)*k*x²
where
k = the spring constant
x = the extension (or compression) of the spring

Given:
k = 470 N/m
x = 17.0 cm = 0.17 m

Therefore
SE = 0.5*(470 N/m)*(0.17 m)² = 6.7915 J

Answer: 6.8 J (nearest tenth)

6 0

4 years ago

A photon of wavelength 3.7 nm Compton scatters from an electron at an angle of 90°. What is the modified wavelength? (Enter your

viva [34]

Answer:

3.70242 nm

Explanation:

Using Compton effect formula

Δλ = ( h / mec) ( 1 - cosθ)

where h is planck constant = 6.62607 × 10 ⁻³⁴ m²kg/s

me, mass of an electron = 9.11 × 10⁻³¹ kg

c is the speed of light = 3 × 10⁸ m/s