7.) Area of a square pyramid is given by A = s^2 + 2sl; where s is the side length of the base and l is the slant height.
Area of given pyramid = 4^2 + (2 x 4 x 7) = 16 + 56 = 72 ft^2
8.) Area of the given pyramid is the area of the hexagonal base plus the area of the six slant triangles.
Area of hexagonal base = (3sqrt(3))/2 x 10^2 = 150 x 1.732 = 259.8
Area of the 6 traingles = 6(1/2 x 10 x 13) = 6 x 65 = 390
Total surface area of the pyramid = 259.8 + 390 = 649.8 ≈ 650 m^2
9.) Using pythagoras rule, the slant height is sqrt(6^2 + 3.5^2) = sqrt(36 + 12.25) = sqrt(48.25) = 6.9 mm
10.) The surface area of a cone is given by πr^2 + πrl
Area = π x 6^2 + π x 6 x 20 = 36π + 120π = 490.1 cm^2
11.) l = sqrt(r^2 + h^2) = sqrt(11^2 + 16^2) = sqrt(121 + 256) = sqrt(377) = 19m
384 pages (0.75) = 288 pages
Add this to the original amount of pages.
384 + 288 = 672 total pages.
Answer:
y = -1
Step-by-step explanation:
The standard form of equation of a line is y = mx+b
m is the slope
b is the y intercept
Get the coordinate of the point of interception of the line 2x - y = 9 and 3x - 7y = 19
Make y the subject of the formula in both expressions
For 2x - y = 9
- y = 9- 2x
y = 2x - 9
Similarly for 3x - 7y = 19
-7y = 19 - 3x
7y = 3x - 19
y = 3/7 x - 19/7
Equating both expressions
2x - 9 = 3/7 x - 19/7
Multiply through ny 7
14x - 63 = 3x - 19
14x - 3x = -19 + 63
11x = 44
x = 44/11
x = 4
Since y =2x - 9
y = 2(4) - 9
y = 8-9
y = -1
Hence the coordinate of intersection is at (4, -1)
Get the equation of the line passing through (-3, -1) and (4, -1)
Slope m = -1+1/4+3
m = 0/7
m = 0
Get the intercept
Substitute m = 0 and (-3, -1) into y = mx+b
-1 = 0(-3) + b
-1 = b
b = -1
Get the required equation
Recall that y = mx + b
y = 0x + (-1)
y = -1
Hence the required equation is y = -1
Answer:
got to settings
Step-by-step explanation:
