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Alexxandr [17]
4 years ago
5

Wang Hao wants to spend at most $15 on dairy products. Each liter of goat milk costs $2.40 and each liter of cow's milk costs $1

.20
Write an inequality that represents the number of liters of goat milk (G) and cow's milk (C) Wang Hao can buy on his budget.
Mathematics
2 answers:
Mashutka [201]4 years ago
8 0

Answer:

2.40g + 1.20c ≤15

Step-by-step explanation:

Each liter of goat milk costs $2.40 and each liter of cow's milk costs $1.20

Let g = liters of goats milk

c = liters of cows milk

What we are buying is the liters times the cost

2.40g + 1.20c

This must be less than or equal to 15 dollars

2.40g + 1.20c ≤15

maksim [4K]4 years ago
5 0

Answer:

2.4G+1.2C is less than or equal to 15

Step-by-step explanation:

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Box 1 contains 1000 lightbulbs of which 10% are defective. Box 2 contains 2000 lightbulbs of which 5% are defective. (a) Suppose
mojhsa [17]

Answer:

a) There is a 66.7% chance that you were given box 1

b) There is a 80% chance that you were given box 1

Step-by-step explanation:

To find this, we need to note that there is a 1/10 chance of getting a defective bulb with box 1 and a 1/20 chance in box 2.

a) To find the answer to this, find the probability of getting a defective bulb for each box. Since there is only one bulb pulled in this example, we just use the base numbers given.

Box 1 = 1/10

Box 2 = 1/2

From this we can see that Box 1 is twice as likely that you get a defective bulb. As a result, the percentage chance would be 2/3 or 66.7%

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4 years ago
A net force of 66 N accelerates a child at 2.0m/s 2 down a smooth playground slide what is the mass of the child?
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8 0
3 years ago
Read 2 more answers
What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9
weeeeeb [17]

The difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

<h3>How to determine the difference?</h3>

The expression is given as:

\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}

Factor the denominators of the expressions:

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}

Apply the difference of two squares to x² - 9

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}

Take LCM

\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Hence, the difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Read more about expressions at:

brainly.com/question/723406

#SPJ4

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