A water sample tested positive for lead with a concentration of 35 ppm. The density of the solution is 1.00 g/mL Which of the fo
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Answer : Option A) 2.00 eV
Explanation : The conversion of J to eV is done with the following formula;
Here, we have the value of particle in terms of Joules which is 3.2 X
So, on substituting we get,
= 3.2 X X 
= 1.99 eV so, it can be rounded off to 2.00 eV.
Explanation : The conversion of J to eV is done with the following formula;
Here, we have the value of particle in terms of Joules which is 3.2 X
So, on substituting we get,