Two identical blocks are attached to the same massless rope, which is strung around two massless, frictionless pulleys. A massle
1 answer:
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Explanation:
In order to compute correctly the sum of the two terms, we have to rewrite one of them such that they have the same exponent.
The two terms are:
For instance, we can re-write the second term such as it also has a power . In order to do that, we have to move the decimal point one place to the left, therefore:
At this point, the two numbers have the same exponent, so we can just add them together by adding the bases and keeping the same exponent, -2:
The radius of the sphere is r=5.15 cm=0.0515 m, and its surface is given by
So the total charge on the surface of the sphere is, using the charge density
:
The electrostatic force between the sphere and the point charge is:
where
ke is the Coulomb's constant
Q is the charge on the sphere
is the point charge
r is their separation
Re-arranging the equation, we can find the separation between the sphere and the point charge:
So the total charge on the surface of the sphere is, using the charge density
The electrostatic force between the sphere and the point charge is:
where
ke is the Coulomb's constant
Q is the charge on the sphere
r is their separation
Re-arranging the equation, we can find the separation between the sphere and the point charge:
Answer:
<em>work done in pumping the entire fuel is 466587 J</em>
<em></em>
Explanation:
weight of the gasoline per volume = 6600 N/m^3
diameter of the tank = 3 m
length of the tank = 2 m
height of the tractor tank above the top of the tank = 5 m
work done in pumping fuel to this height = ?
First, we find the volume of the fuel
since the tank is cylindrical,<em> we assume that the fuel within also takes the cylindrical shape.</em>
<em>Also, we assume that the fuel completely fills the tank.</em>
volume of a cylinder =
where r = radius = diameter ÷ 2 = 3/2 = 1.5 m
volume of the cylinder = 3.142 x x 2 = 14.139 m^3
we then find the total weight of the fuel in Newton
total weight = (weight per volume) x volume
total weight = 6600 x 14.139 = 93317.4 N
work done = (total weight of the fuel) x (height through which the fuel is pumped)
work done in pumping = 93317.4 x 5 = <em>466587 J</em>