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murzikaleks [220]
3 years ago
13

Why is the principle of periodic motion used in pendulum and quartz clocks?

Physics
1 answer:
trasher [3.6K]3 years ago
5 0

Answer:

A pendulum of given length always takes the same time to complete one oscillation. The time period of a pendulum of given length is constant. Thus, the periodic motion of pendulum has been used to make pendulum clocks for measuring time.

Explanation:

Hope it's answer you !plz mark as brainlist!

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When you're 10 or 20 miles away from the origin of an earthquake, the P-waves get to you a little bit before the S-waves. Which
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Explanation:

P, Primary, or Compressional waves travel the fastest (~6 km/sec in the upper crust). They cause the matter to oscillate forward and backward, parallel to the motion of the seismic wavefront. P waves push (compress) and pull (dilate) the rock that they pass through.

yor answe is (B)

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3 years ago
What two things affect the density of Water?
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The temperature of the water and the and the salinity of water
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Can someone please give me the answers to this? ... please ...
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3. 2 meters per second 4. i think object 7. i’ll try to figure it out 8. .77 9. 25km 10. 10m each second
7 0
3 years ago
A single conservative force F = (7.0x - 11) N, where x is in meters, acts on a particle moving along an x axis. The potential en
Umnica [9.8K]

Answer:

(a) 34.6429J

(b) -1.57 m

(c) 4.71 m

Explanation:

The derivative of the potential energy with respect to the position is equal to the negative of the force, so:

-\frac{dU}{dx}=F\\ dU=-Fdx

Then, if we integer both sides, we get:

∫dU = -∫(7x - 11)dx

U=\frac{-7}{2}x^{2} + 11x + c

we know that U is equal to 26 J when x is zero, so:

U=\frac{-7}{2}x^{2} + 11x + c

26=\frac{-7}{2}(0)^{2} + 11(0) + c

26=c

Finally, the equation for the potential energy is:

U(x)=\frac{-7}{2}x^{2} + 11x + 26

Therefore, the maximum positive potential energy is the energy when x is equal to 11/7. That is because the equation of U is the equation of a parable, and the vertex in a parable is given by:

x=\frac{-b}{2a} = \frac{-11}{2(-7/2)} =\frac{11}{7}

Where b is the number beside x and a is the number beside x^{2}, Then, the value of maximum U is:

U(11/7)=\frac{-7}{2}(11/7)^{2} + 11(11/7) + 26

U(11/7)=34.6429J

On the other hand, the negative and positive values of x where the potential energy is equal to zero is calculated as:

U(x)=\frac{-7}{2}x^{2} + 11x + 26

0=\frac{-7}{2}x^{2} + 11x + 26

if we solve this using the quadratic equation, we get:

x =\frac{-11+\sqrt{11^{2}-4(-7/2)(26)} }{2(-7/2)}=-1.5747

x =\frac{-11-\sqrt{11^{2}-4(-7/2)(26)} }{2(-7/2)}=4.7175

Finally, the negative and positive values of x where the potential energy is equal to zero are -1.5747 and 4.7175 respectively.

3 0
3 years ago
A constant force of 560 n was applied to a rock. If 2700j of energy was used to move the rock, how far did the rock move
larisa [96]

Answer:

Work done = Force X Distance

Work done/Force = Distance

2700/560 = Distance

Distance = 4.8 meters

4 0
4 years ago
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