Question

Calculate the height of a cliff if it takes 2.35 s for a rock to hit the ground when it is thrown straight up from the cliff with an initial velocity of 8.00

Answer 1

Answer:

height of a cliff is 45.86 m

Explanation:

u=8 m/s

t=2.35 s

the height of the cliff is

$S=ut+\frac{1}{2} at^2\\S=8\times2.35+\frac{1}{2} \times 9.8 \times 2.35^2\\S=45.86 m$