All categories

3 years ago

I need help please I forgot how to do this

Mathematics

2 answers:

Savatey [412]3 years ago

4 0

Answer:

no it is not proportional

Artemon [7]3 years ago

4 0

Answer:

No 3/9 would be proportional to 6/18

Step-by-step explanation:

I think

You might be interested in

What is the expression 4c - 3 when c = 2

harkovskaia [24]

The expression -> 4 • 2 - 3
the answer to the expression would be 5

4 0

3 years ago

Find the volume of the square pyramid below.

miv72 [106K]

Hello!

$\bf ANSWER$

The volume of the square pyramid is approximately $\boxed{ \bf 19.19~km^3}$

____________________________________________________________

$\bf EXPLANATION$

V = $a^{2}$ $\frac{h}{3}$

First, we must find the area of the square base.

A = l * w

A = 3.5 * 3.5

A = 12.25 km^2

The area of the base is 12.25 km^2. Now, multiply the base area by the perpendicular height. Then divide by 3.

V = (12.25 * 4.7) / 3

V = 19.1916666667

V ≈ 19.19 km^3

7 0

3 years ago

Please help I don’t wanna add a bunch of points Bc nobody is helping me I’m just wasting them.

Ede4ka [16]

Answer:Cross multiply and solve for x.

x/6 = 5/1.25

let the height of building be h ft

h/6 = 60/15

h = 6(60/15) = 24

the building is 24 ft high

Step-by-step explanation:

Well first let’s covert the ft to in- 5ft is 60 in and 6ft is 72 in. Then we want to set up 2 fractions based on height and shadow, so we have 60/15=x/72 (we put x because that’s what we’re trying to find). Then we do cross multiplication so now we have 15x=4320. We divide 15, so now we have 4320/15=288. So the building is 288 in tall or 24ft tall! Glad to help! :)

3 0

2 years ago

Sasha buys two ribbons of equal length. She cuts 9 pieces of the same length, L, from the first ribbon and finds that 5 inches a

nikitadnepr [17]

Answer:

50 inches.

Step-by-step explanation:

Let the length of the each ribbon was x.

Now, she cuts 9 pieces of same length L which means total length is 9L.

Now, doing the same she was left with 5 inches of ribbon. Hence, we have

[tex[9L+5=x.....(1)[/tex]

Similarly, we can write a equation for the second situation.