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likoan [24]
4 years ago
14

The mass of a 50-mL volumetric flask is 40.638 g. After adding 15.0 mL of 95% ethanol and adding enough water to complete the vo

lume to 50.00 mL, the flask weighed 88.219 g. What is the density of the mixture?
Chemistry
1 answer:
Nuetrik [128]4 years ago
3 0

Answer

0.9516 grams / mL (50.00 has 4 sig digs.)

Remark

You have a couple of extraneous numbers there. You don't care about anything except the mass of the flask +  water/alcohol mixture  (88.219 grams). and the mass of the flask (40.638 grams)

Formulas

  • mass water/alcohol mixture = mass of the flask with fluid - mass flask
  • density = mass / volume

Solution

mass water/alcohol mixture = 88.219 - 40.638 = 47.581

  • Volume = 50 mL
  • Density = mass / Volume
  • Density = 47.581/50
  • Density = 0.95162  There are 4 sig digs so the answer should be
  • 0.9516
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8.0 mol AgNO3 reacts with 5.0 mol Zn in
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Taking into account the reaction stoichiometry, 8 moles of Ag can be produced from 8 moles of AgNO₃ and 5 moles of Zn.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 AgNO₃ + Zn → 2 Ag + Zn(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • AgNO₃: 2 moles
  • Zn: 1 mole
  • Ag: 2 moles
  • Zn(NO₃)₂: 1 mole

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Zn reacts with 2 moles of AgNO₃, 5 moles of Zn reacts with how many moles of AgNO₃?

amount of moles of AgNO_{3}= \frac{5 moles of Znx2 moles of AgNO_{3}}{1 mole of Zn}

<u><em>amount of moles of AgNO₃= 10 moles </em></u>

But 10 moles of AgNO₃ are not available, 8 moles are available. Since you have less moles than you need to react with 5 moles of Zn, AgNO₃ will be the limiting reagent.

<h3>Moles of Ag formed</h3>

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 2 moles of AgNO₃ form 2 moles of Ag, 8 moles of AgNO₃ form how many moles of Ag?

amount of moles of Ag=\frac{8 moles of AgNO_{3}x2 moles of Ag }{2 moles of AgNO_{3}}

<u><em>amount of moles of Ag= 8 moles</em></u>

Then, 8 moles of Ag can be produced from 8 moles of AgNO₃ and 5 moles of Zn.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

#SPJ1

4 0
2 years ago
What is the standard heat of reaction for the following reaction?
8090 [49]

Answer:

The correct answer to the question is

The standard heat of reaction for the reaction is

a. 216.8 kJ released per mole

Explanation:

The heat of reaction is given by [Heat of formation of products] - [Heat of formation of reactants]

In the question we have, heat of formation of the products Zn+2 (aq) = -152.4 kJ/mole and the heat of formation of the reactants = 64.4 kJ/mole

Therefore, the heat of formation of the reaction = (-152-64.4) kJ/mole or

-216.8 kJ/mole released

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4 years ago
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