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Rus_ich [418]
3 years ago
7

3. In all cells, genetic materials are stored in the

Chemistry
2 answers:
Rainbow [258]3 years ago
5 0
Nucleus c
Because it is the powerhouse of the cell
jasenka [17]3 years ago
3 0
The answer is C the nucleus
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To what temperature must a balloon, initially at 25°c and 2.00 l, be heated in order to have a volume of 6.00 l? question 8 opti
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How many grams of hydrogen chloride can be produced from 1g of hydrogen and 55g of chlorine? What is the limiting reactant?
vova2212 [387]

Answer:

The limiting reactant is hydrogen, and the grams HCl produced is 36.175 g.

Explanation:

Balanced equation is 2 H + Cl2 = 2 HCl.

First thing, convert grams to moles via using molar mass.

Molar mass for hydrogen is 1.0079 g/mol. 1g x 1 mol / 1.0079 g = 0.99216 mol.

Molar mass for chlorine is 70.906 g/mol. 55g x 1 mol / 70.906 g = 0.7756748 mol.

Next, determine which is the limiting reactant - probably the fastest way to do it is just to take one of the reactants, say it's the limiting one, and calculate how much of the other reactant would be needed if that really was the limiting reactant, and then compare it to the actual moles of reactant available.

If hydrogen was the limiting reactant at 0.992 mol, you'd need .496 mol of Cl2 to complete the reaction.

If chloride was the limiting reactant at 0.776 mol, you'd need 1.55 mol of H to complete the reaction.

Comparing these numbers to the amounts we actually have available, the limiting reactant is hydrogen.

Once you've determined that, just plug in the amounts to the balanced equation to get the number of moles of HCL produced, which in this case, is just 0.992 mol.

Now, reverse the process that you took to get the moles of reactant, and you have the grams of product produced.

0.992 mol x 36.4609 g / 1 mol = 36.175 g.

7 0
3 years ago
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musickatia [10]

Answ burh i dont even know

Explanation: i dont even know this

7 0
3 years ago
If you start with 4.3 moles of NH3, how many moles of NANH2 can be produced
mash [69]

Explanation:

Mole ratio of NH3 to NaNH2 = 2 : 2.

Moles of NaNH2 produced

= 4.3mol * (2/2) = 4.3mol.

4 0
2 years ago
How much concentrated 5.0M nitric acid is needed to prepare 50 mL of a 1.0 M solution?
Ksivusya [100]

Explanation:

Volume is the quantity of three-dimensional  

6 0
2 years ago
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